CODEWITHSUNDEEP
javaloopsfor-loopwhile-loop
Rad
Rad

Reputation: 63

How can I output several numbers per line in java

Hi I am new in programming,so please don't laugh from my stupid question.

I wrote program which ask user for input a number than program should output all the numbers from 0 to that entered number(doesn't matter if it is positive or negative). I have tried 3 different versions

Here is my code:

int min = Integer.MIN_VALUE;
int max = Integer.MAX_VALUE;
int num = PutiL.validNum(min, max, "number");
//this my utility methode which check if number is in range and if it is not a double or letter
int i = 0, z;
int y = 0;

//3rd version
while (i <= num) {
    for (z = 0; z < 4; z++) {
        System.out.print(i + " ");
        i++;
    }
    System.out.println();
}

//2nd version
if (num > 0) {
    for (i = 0; i <= num; y++) {
        for (z = 0; z < 4; z++) {
           System.out.print(i + ",");
            i++;
        }
        System.out.println();
    }
} else {
    for (i = 0; i > num; y--) {
        for (z = 0; z < 4; z++) {
           System.out.print(i + ",");
            i--;
        }
        System.out.println();
    }
}

//1st version`enter code here`
if (num > 0) {
    for (i = 0; i <= num; i++)
    {
       System.out.print(i + ",");
    }
} else {
    for (i = 0; i >= num; i--) {
        System.out.print(i + ",");
    }
}
System.out.println();

Problem is that code doesn't stop straight after number typed in by user. Will someone give me a hint what is wrong as I don't have any more ideas.

And here is the PutiL methode

public static int validNum(int min, int max, String words) {
    int num;

    do {
        System.out.println("Please enter " + words);
        while (!kb.hasNextInt()) {
            System.out.println("Please re-enter ");
            kb.nextLine();
        }
        num = kb.nextInt();

        if (num < min || num > max) {
            System.out.println("Not in range - re-enter\tproper range is "
                    + min + " - " + max);
        }

    } while (num < min || num > max);
    return num;
}

Upvotes: 1

Views: 3229

Answers (5)

Rad
Rad

Reputation: 63

Thank you all for help I solve it my self was really easy here is code I useit and now its work perfectly

for(i = 0; i <= num; i++)
        {
            System.out.print(i + " ");
            y++;
            if(y % 4 == 0)
            {
                System.out.println();
            }
        }
        for(i = 0; i >= num; i--)
        {
            System.out.print(i + " ");
            y++;
            if(y % 4 == 0)
            {
                System.out.println();
            }
        }

But thank you all again for giving my ideas.

Upvotes: 0

mikey
mikey

Reputation: 5160

"program should output all the numbers from 0 to that entered number" and "I want them print for example 4 in a one line and than skip to another line"

if(num >=0) {

  for (z = 0; z <= num; z++)
  {
    System.out.print(z + " ");
    if(z > 0 && z%4==0)
      System.out.println();
  }

}
else {
  // similar loop for negatives
}
System.out.println();

Upvotes: 0

Viktor
Viktor

Reputation: 11

This will give the user a dialog and the value the user enters will count to zero.

First import:

import javax.swing.JOptionPane.*;

Then:

int user_choice = Integer.parseInt(
showInputDialog(null, "Please enter a number."));

if(user_choice > 0){
  for(int temp = 0; temp <= user_choice; temp++){
  System.out.println(temp);    
  }
}
else{
  for(int temp = 0; temp >= user_choice; temp--){
  System.out.println(temp);    
  }
}

Upvotes: 0

devconsole
devconsole

Reputation: 7915

public static void main(String[] args) {
    int number = Integer.parseInt(args[0]);
    if (number >= 0) {
        for (int i = 0; i <= number; i++) {
            System.out.println(i);
        }
    } else {
        for (int i = 0; i >= number; i--) {
            System.out.println(i);
        }
    }
}

Or a bit more concise and with duplicating the println statement...

public static void main(String[] args) {
    int number = Integer.parseInt(args[0]);
    int increment = number >= 0 ? 1 : -1;
    for (int i = 0; i != number + increment; i += increment) {
        System.out.println(i);
    }
}

Upvotes: 0

Ahmad Azwar Anas
Ahmad Azwar Anas

Reputation: 1287

//2nd version
if (num > 0)
{
    for (i = 0; i <= num; y++)  <== THIS MAKE INFINITE too, OKAY.. ^^, change i to stop
    {
        for (z = 0; z < 4; z++)
        {
           System.out.print(i + ",");
            i++;
        }
        System.out.println();
    }
} else
{
    for (i = 0; i > num; y--) <== THIS MAKE INFINITE LOOPS, OKAY.. ^^, it must i to stop
    {
        for (z = 0; z < 4; z++)
        {
           System.out.print(i + ",");
            i--;
        }
        System.out.println();
    }
}

don't forget to accepted the answer if it goes right.. ^^

Upvotes: 1

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