CODEWITHSUNDEEP
java
Ayoub Eloumari
Ayoub Eloumari

Reputation: 7

print many values by a loop in java

public class teste {

public static void main(String[] args) {
    int t1=5;
    int t2=10;
    int t3=30;

    for(int i=1;i<4;i++)
    {
        System.out.println("t"+i);
    }

}}

Hi guys I don't know if it exists in java but I wanna print t1 t2 t3 by a loop, for example for i=1 t(i=1) => t1 so it will give us 5, how can I do that, and thank you all.

Upvotes: 0

Views: 171

Answers (5)

Sandile Stanza Maseko
Sandile Stanza Maseko

Reputation: 11

The for loop will only print the values t1, t2,t3 only because you initialized the t1 as a variable and in your output you using it as a text by including quotation marks. Try this code.

public class test
{
    public static void main(String[] args) {
        int [] arrValue = {5 , 10 , 30};

        for(int i= 0; i <4; i++)
        {
            System.out.println("t"+i + "=" + arrValue[i]);
        }
    }
}

Upvotes: 0

Andrew S
Andrew S

Reputation: 2801

Can "t" + i be considered a key (instead of a dynamic variable name which is not supported)? If that fits the context then a Map could be used. For example:

public static void main(String[] args) {
    Map<String, Integer> tVals = new HashMap<>();
    tVals.put("t1", 5);
    tVals.put("t2", 10);
    tVals.put("t3", 30);

    for (int i = 1; i < 4; i++) {
        System.out.println(tVals.get("t" + i));
    }
}

Upvotes: 0

javascaped
javascaped

Reputation: 31

Please tell me if I don't understand your question. What you seem to be trying is to print t1 t2 and t3, but based on the i of the for loop right? So you think that t + i should first be t1, then t2 then t3 and finally output those values. That doesn't work for any language this way. First of all, t is a char, while 1 2 or 3 is an integer. Secondly, if you put it like that in System.out.println it basically means "print out t and then i", instead of "print out what t+i would be (as initialized)". I might not be very clear with explaining. Anyway, you should use an array.

Try the following:

class test{

    public static void main(String[] args) {

        int[] anArray = { 
        5, 10, 30,
    };

        for(int i = 0; i < anArray.length; i++)
        {
            System.out.println(anArray[i]);

        }
    }

}

Upvotes: -1

Pavneet_Singh
Pavneet_Singh

Reputation: 37414

3 variables mean three atomic statements are required but to access them in continuous way , collect them in some container like array so use

int t1=5;
int t2=10;
int t3=30;
int[] arr = {t1,t2,t3}; // array index start from 0
//           0  1  2
// arr[0] is 5
// arr[1] is 10 and so on

for(int i=0;i<3;i++)
{
    System.out.println(arr[i]);
}

Other option: use var args which is still sort of an array but flexible like

static void printNums(int... arr){
    for(int i=0;i<arr.length;i++)
    {
        System.out.println(arr[i]);
    }
}

and call it like 

printNums(t1,t2);
printNums(t1,t2,t3);
printNums(1,2,3,4,5,6);

Upvotes: 3

azro
azro

Reputation: 54168

There is no way to call a variable using String or int or whatever

But that's the purpose of arrays, first index is 0 and last one is length-1 (here 2)

int[] t = new int[]{5, 10, 30};

for(int i=0 ; i<t.length ; i++){
    System.out.println(t[i]);
}
// gives
5
10
30

Upvotes: 1

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