CODEWITHSUNDEEP
cdebuggingswitch-statement
aditya
aditya

Reputation: 165

what happens when there are two continuous breaks in a switch statement?

#include <stdio.h>
int main()
{
    int i = 0;
    char c = 'a';
    while (i < 2){
        i++;
        switch (c) {
        case 'a':
            printf("%c ", c);
            break;
            break;
        }
    }
    printf("after loop\n");
}

What will be the output of the above code? Does the second break mean anything?

Upvotes: 1

Views: 187

Answers (2)

sajinmp
sajinmp

Reputation: 518

There is no use for a second break statement. The break statement has the following two usages:

  • When the break statement is encountered inside a loop, the loop is immediately terminated and program control resumes at the next statement following the loop.

  • It can be used to terminate a case in the switch statement.

In this case it terminates the case statement. So the second break doesn't get called. It is a useless statement.

Upvotes: 4

AnT stands with Russia
AnT stands with Russia

Reputation: 320641

break is a jump statement in C. It unconditionally transfers control to a different location in the code. Which means that any code between that break and the target point of the jump is unreachable, unless there's a label that allows one to reach it.

In your case there's no such label. The second break is unreachable and has no effect.

Upvotes: 5

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