CODEWITHSUNDEEP
c#integer-overflow
NLV
NLV

Reputation: 21661

Incrementing an integer value beyond its integer limit - C#

I've a for loop which keeps incrementing an integer value till the loop completes. So if the limit n is a double variable and the incremented variable 'i' is an integer, i gets incremented beyond its limits.

 double total = 0;
 double number = hugetValue;
 for (int i = 1; i <= number; i++)
 {
    total = total + i;
 }
 return total;

What happens to 'i' if it exceeds its capacity? How the value of i changes? Will i get a runtime error?

Upvotes: 19

Views: 15477

Answers (3)

paxdiablo
paxdiablo

Reputation: 882186

Similar to the behaviour in some implentations of C where an int just wraps around from INT_MAX to INT_MIN ( though it's actually undefined behaviour according to the ISO standard), C# also wraps. Testing it in VS2008 with:

int x = 2147483647;
if (x+1 < x) {
    MessageBox.Show("It wrapped...");
}

will result in the message box appering.

If your hugetValue is greater than the maximum int value, then your loop will run forever because of this.

For example, if it's 2147483648, just as you think you're getting close to it, the int wraps around from 2147483647 back to -2147483648 and the loop just keeps on going.

Upvotes: 13

djna
djna

Reputation: 55937

Apologies if this seems rude, but you will learn far more by trying this yourself.

Edited: aha, so you did try it, and got unexpected results. As has been explained elsewhere C-like languages tend to quietly wrap integer arithmetic. That's actually quite a reasonable behaviour in general if the cost of checking for overflow is high. Once you know that this can happen one codes carefully, especially watching for the kind of construct in your example.

Upvotes: 2

leppie
leppie

Reputation: 117300

If you want an exception, either supply the checked compiler option, or use the checked construct provided in C#.

Upvotes: 3

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