CODEWITHSUNDEEP
file-uploadasp.net-web-apifiddler
SHEKHAR SHETE
SHEKHAR SHETE

Reputation: 6056

How to Post a file using Fiddler to WebAPI using C#?

I am new to ASP.NET Web API. I have a sample FileUpload web api (from some site) to upload files to the server. But, don't know how to test it using Fiddler.

http://localhost:54208/myapi/api/webapi/FileUpload

On test.aspx page: Following works fine. I want to know how to use this API using Fiddler?

<html xmlns="http://www.w3.org/1999/xhtml">
<head runat="server">
    <title></title>
</head>
<body>

  <form enctype="multipart/form-data" method="post" action="http://localhost:54208/myapi/api/webapi/FileUpload" id="ajaxUploadForm" novalidate="novalidate">

            <fieldset>
                <legend>Upload Form</legend>
                <ol>
                    <li>
                        <label>Description </label>
                        <input type="text" style="width:317px" name="description" id="description">
                    </li>
                    <li>
                        <label>upload </label>
                        <input type="file" id="fileInput" name="fileInput" multiple>
                    </li>
                    <li>
                        <input type="submit" value="Upload" id="ajaxUploadButton" class="btn">
                    </li>
                </ol>
            </fieldset>
        </form>

</body>
</html>


public async Task<HttpResponseMessage> FileUpload()
       {
           // Check whether the POST operation is MultiPart?
           if (!Request.Content.IsMimeMultipartContent())
           {
               throw new HttpResponseException(HttpStatusCode.UnsupportedMediaType);
           }

           // Prepare CustomMultipartFormDataStreamProvider in which our multipart form
           // data will be loaded.
           //string fileSaveLocation = HttpContext.Current.Server.MapPath("~/App_Data");
           string fileSaveLocation = HttpContext.Current.Server.MapPath("~/UploadedFiles");
           CustomMultipartFormDataStreamProvider provider = new CustomMultipartFormDataStreamProvider(fileSaveLocation);
           List<string> files = new List<string>();

           try
           {
               // Read all contents of multipart message into CustomMultipartFormDataStreamProvider.
               await Request.Content.ReadAsMultipartAsync(provider);

               foreach (MultipartFileData file in provider.FileData)
               {
                   files.Add(Path.GetFileName(file.LocalFileName));
               }

               // Send OK Response along with saved file names to the client.
               return Request.CreateResponse(HttpStatusCode.OK, files);
           }
           catch (System.Exception e)
           {
               return Request.CreateErrorResponse(HttpStatusCode.InternalServerError, e);
           }
       }
       // We implement MultipartFormDataStreamProvider to override the filename of File which
       // will be stored on server, or else the default name will be of the format like Body-
       // Part_{GUID}. In the following implementation we simply get the FileName from 
       // ContentDisposition Header of the Request Body.
       public class CustomMultipartFormDataStreamProvider : MultipartFormDataStreamProvider
       {
           public CustomMultipartFormDataStreamProvider(string path) : base(path) { }

           public override string GetLocalFileName(HttpContentHeaders headers)
           {
               return headers.ContentDisposition.FileName.Replace("\"", string.Empty);
           }
       }

Help Appreciated!

Upvotes: 0

Views: 2242

Answers (1)

Murali Krishna
Murali Krishna

Reputation: 167

Go to fiddler, select post type, give your local web api url. In request body just upload file and execute, it will go to webapi method directly. Controller method should be [HttpPost]

Upvotes: 1

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