CODEWITHSUNDEEP
pythonmathfor-looplist-comprehension
ibrahim
ibrahim

Reputation: 109

Check what numbers in a list are divisible by certain numbers?

Write a function that receives a list of numbers and a list of terms and returns only the elements that are divisible by all of those terms. You must use two nested list comprehensions to solve it.

divisible_numbers([12, 11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1], [2, 3]) # returns [12, 6]

def divisible_numbers(a_list, a_list_of_terms):

I have a vague pseudo code so far, that consists of check list, check if divisible if it is append to a new list, check new list check if divisible by next term and repeat until, you have gone through all terms, I don't want anyone to do this for me but maybe a hint in the correct direction?

Upvotes: 3

Views: 9026

Answers (2)

peniel charles
peniel charles

Reputation: 1

if you want to get input from the user using this type of way.

enter code hereprint("numbers which are divisible by 5")
user_input=eval(input("enter the value in list type [1,2,3]: "))**
print(type(user_input)) if type(user_input)==list: for i in
user_input: if(i%5==0): print(i,end=",") else:
    print("none")

OUTPUT:

numbers that are divisible by 5 enter the value in list type [1,2,3]:
   [15,10,20,45,69] <class 'list'> 15,10,20,45,

Upvotes: 0

Cory Kramer
Cory Kramer

Reputation: 117866

The inner expression should check if for a particular number, that number is evenly divisible by all of the terms in the second list

all(i%j==0 for j in a_list_of_terms)

Then an outer list comprehension to iterate through the items of the first list

[i for i in a_list if all(i%j==0 for j in a_list_of_terms)]

All together

def divisible_numbers(a_list, a_list_of_terms):
    return [i for i in a_list if all(i%j==0 for j in a_list_of_terms)]

Testing

>>> divisible_numbers([12, 11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1], [2, 3])
[12, 6]

Upvotes: 9

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