Reputation: 932
I am currently trying to make use of Pandas MultiIndex attribute. I am trying to group an existing DataFrame-object df_original
based on its columns in a smart way, and was therefore thinking of MultiIndex.
print df_original =
by_currency by_portfolio A B C
1 AUD a 1 2 3
2 AUD b 4 5 6
3 AUD c 7 8 9
4 AUD d 10 11 12
5 CHF a 13 14 15
6 CHF b 16 17 18
7 CHF c 19 20 21
8 CHF d 22 23 24
Now, what I would like to have is a MultiIndex DataFrame-object, with A, B
and C
, and by_portfolio
as indices. Looking like
CHF AUD
A a 13 1
b 16 4
c 19 7
d 22 10
B a 14 2
b 17 5
c 20 8
d 23 11
C a 15 3
b 18 6
c 21 9
d 24 12
I have tried making all columns in df_original
and the sought after indices into list-objects, and from there create a new DataFrame. This seems a bit cumbersome, and I can't figure out how to add the actual values after.
Perhaps some sort of groupby
is better for this purpose? Thing is I will need to be able to add this data to another, similar, DataFrame, so I will need the resulting DataFrame to be able to be added to another one later on.
Thanks
Upvotes: 0
Views: 181
Reputation: 139162
You can use a combination of stack
and unstack
:
In [50]: df.set_index(['by_currency', 'by_portfolio']).stack().unstack(0)
Out[50]:
by_currency AUD CHF
by_portfolio
a A 1 13
B 2 14
C 3 15
b A 4 16
B 5 17
C 6 18
c A 7 19
B 8 20
C 9 21
d A 10 22
B 11 23
C 12 24
To obtain your desired result, we only need to swap the levels of the index:
In [51]: df2 = df.set_index(['by_currency', 'by_portfolio']).stack().unstack(0)
In [52]: df2.columns.name = None
In [53]: df2.index = df2.index.swaplevel(0,1)
In [55]: df2 = df2.sort_index()
In [56]: df2
Out[56]:
AUD CHF
by_portfolio
A a 1 13
b 4 16
c 7 19
d 10 22
B a 2 14
b 5 17
c 8 20
d 11 23
C a 3 15
b 6 18
c 9 21
d 12 24
Upvotes: 3