CODEWITHSUNDEEP
pythonpygame
Yoweli Kachala
Yoweli Kachala

Reputation: 423

How to play a sound when my bluetooth device is detected

Started with python programming this morning and wanted to make a simple application that sniffs my phone's Bluetooth when I am around and play a song. This app continues to search for my bluetooth every 27 seconds. If I am still around, it will continue playing but I leave or switch off my bluetooth, I want it to stop the song. I have the following code, everything works fine but I get an error that stops the execution if there is no bluetooth device detected and when I leave or switch off my device, the song continues to play. Please help.

import socket
import mmap
from bluetooth import *
import msvcrt
import bluetooth
import pygame, time

from pygame.locals import *

pygame.mixer.pre_init(44100, 16, 2, 4096) #frequency, size, channels, buffersize
pygame.init() #turn all of pygame on.
DISPLAYSURF = pygame.display.set_mode((500, 400))
soundObj = pygame.mixer.Sound('sleep.wav')

target_name = "Joelk"
target_address = None

loop = False
isHome = False
playing = False

print("Press Esc to end....")
while loop == False:
    print("Perfoming Enquire")

    if msvcrt.kbhit():
        if ord(msvcrt.getch()) == 27:
            break
   nearby_devices = discover_devices(lookup_names = True)
print ("found %d devices" % len(nearby_devices))

if 0 == len(nearby_devices):
    print("There is no device nearby")
else:
    print("There is a device")
    for name, addr in nearby_devices:
        print (" %s - %s" % (addr, name))
        if "Joelk" == addr:
            isHome = True

    if(isHome == True):
        if(playing == True):
            print("Playing")
        else:
            soundObj.play()
            playing = True
    else:
        isHome = False
        soundObj.stop()
        print("Not Playing")

Upvotes: 1

Views: 2397

Answers (1)

BlackJack
BlackJack

Reputation: 4679

You never set is_home to False within the main loop. The only assignment to False happens in an else branch that is only executed iff is_home was False anyway so this statement has no effect.

It has to be set to false if no suitable bluetooth device is detected. This can be done with the help of break and an else clause on the for loop over the detected devices.

Without all the unnecessary imports, without star imports, without unnecessary names, without unnecessary parenthesis and comparisons to bool literals, and untested:

import pygame
from bluetooth import discover_devices


def main():
    pygame.mixer.pre_init(44100, 16, 2, 4096)
    pygame.init()
    _display = pygame.display.set_mode((500, 400))
    sound = pygame.mixer.Sound('sleep.wav')

    is_home = False
    print('Press Esc to end....')
    while True:
        print('Performing Enquire')

        for event in pygame.event.get():
            if event.type == pygame.KEYUP and event.key == pygame.K_ESCAPE:
                break

        nearby_devices = discover_devices(lookup_names=True)
        print('found {0} devices'.format(len(nearby_devices)))
        if nearby_devices:
            for address, name in nearby_devices:
                print(' {0} - {1}'.format(address, name))
                if name == 'Joelk':
                    is_home = True
                    break
            else:
                is_home = False

            if is_home:
                if sound.get_num_channels() > 0:
                    print('Playing')
                else:
                    sound.play()
            else:
                sound.stop()
                print('Not Playing')


if __name__ == '__main__':
    main()

The playing flag was replaced by querying the Sound object on how many channels it is currently playing. If you wand the sound playing in a gapless loop you should have a look at the optional arguments of the play() method regarding looping the sound.

Upvotes: 1

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