Reputation: 122348
How to extract and ignore span in HTML markup?
My input looks like this:
<ul class="definitions">
<li><span>noun</span> the joining together of businesses which deal with different stages in the production or <a href="sale.html">sale</a> of the same <u slug="product">product</u>, as when a restaurant <a href="chain.html">chain</a> takes over a <a href="wine.html">wine</a> importer</li></ul>
Desired outputs:
label = 'noun' # String embedded between <span>...</span>
meaning = 'the joining together of businesses which deal with different stages in the production or sale of the same product, as when a restaurant chain takes over a wine importer' # the text without the string embedded within <span>...</span>
related_to = ['sale', 'chain', 'wine'] # String embedded between <a>...</a>
utag = ['product'] # String embedded between <u>...</u>
I've tried this:
>>> from bs4 import BeautifulSoup
>>> text = '''<ul class="definitions">
... <li><span>noun</span> the joining together of businesses which deal with different stages in the production or <a href="sale.html">sale</a> of the same <u slug="product">product</u>, as when a restaurant <a href="chain.html">chain</a> takes over a <a href="wine.html">wine</a> importer</li></ul>'''
>>> bsoup = BeautifulSoup(text)
>>> bsoup.text
u'\nnoun the joining together of businesses which deal with different stages in the production or sale of the same product, as when a restaurant chain takes over a wine importer'
# Getting the `label`
>>> label = bsoup.find('span')
>>> label
<span>noun</span>
>>> label = bsoup.find('span').text
>>> label
u'noun'
# Getting the text.
>>> bsoup.text.strip()
u'noun the joining together of businesses which deal with different stages in the production or sale of the same product, as when a restaurant chain takes over a wine importer'
>>> bsoup.text.strip
>>> definition = bsoup.text.strip()
>>> definition = definition.partition(' ')[2] if definition.split()[0] == label else definition
>>> definition
u'the joining together of businesses which deal with different stages in the production or sale of the same product, as when a restaurant chain takes over a wine importer'
# Getting the related_to and utag
>>> related_to = [r.text for r in bsoup.find_all('a')]
>>> related_to
[u'sale', u'chain', u'wine']
>>> related_to = [r.text for r in bsoup.find_all('u')]
>>> related_to = [r.text for r in bsoup.find_all('a')]
>>> utag = [r.text for r in bsoup.find_all('u')]
>>> related_to
[u'sale', u'chain', u'wine']
>>> utag
[u'product']
Using BeautifulSoup is okay but it's a little verbose to get what's needed.
Is there any other to achieve the same outputs?
Is there a regex way with some groups to catch the desired outputs?
Upvotes: 4
Views: 340
Reputation: 471
PyQuery is another option to using BeautifulSoup. It follows a jQuery like syntax for extracting info out of html.
Also, for regex...something like below can be used.
import re
text = """<ul class="definitions"><li><span>noun</span> the joining together of businesses which deal with different stages in the production or <a href="sale.html">sale</a> of the same <u slug="product">product</u>, as when a restaurant <a href="chain.html">chain</a> takes over a <a href="wine.html">wine</a> importer</li></ul>"""
match_pattern = re.compile(r"""
(?P<label>(?<=<span>)\w+?(?=</span>)) # create the label \
item for groupdict()
""", re.VERBOSE)
match = match_pattern.search(text)
match.groupdict()
outputs:
{'label': 'noun'}
Using the above as a template, you can build on that with respect to the other html tags too. It uses (?P<name>...)
to name the matched pattern (i.e. label) and then a (?=...)
lookahead assersion and a positive lookbehind assertion to perform the match.
Also, look in to findall or finditer if you have a doc that has more than once instance of your mentioned text pattern.
Upvotes: 1
Reputation: 474271
It still has a pretty well-formed structure and you've stated the set of rules clearly. I would still approach it with BeautifulSoup
applying the "Extract Method" refactoring method:
from pprint import pprint
from bs4 import BeautifulSoup
data = """
<ul class="definitions">
<li><span>noun</span> the joining together of businesses which deal with different stages in the production or <a href="sale.html">sale</a> of the same <u slug="product">product</u>, as when a restaurant <a href="chain.html">chain</a> takes over a <a href="wine.html">wine</a> importer</li></ul>
"""
def get_info(elm):
label = elm.find("span")
return {
"label": label.text,
"meaning": "".join(getattr(sibling, "text", sibling) for sibling in label.next_siblings).strip(),
"related_to": [a.text for a in elm.find_all("a")],
"utag": [u.text for u in elm.find_all("u")]
}
soup = BeautifulSoup(data, "html.parser")
pprint(get_info(soup.li))
Prints:
{'label': u'noun',
'meaning': u'the joining together of businesses which deal with different stages in the production or sale of the same product, as when a restaurant chain takes over a wine importer',
'related_to': [u'sale', u'chain', u'wine'],
'utag': [u'product']}
Upvotes: 2