CODEWITHSUNDEEP
javascriptjqueryprototypeprototypal-inheritance
nitte93
nitte93

Reputation: 1840

Javascript Prototype property : Prototype based Inheritance

I'm confused with Javascript's prototype property. See the below Code.

var s = 12;
var s1 = new String();

console.log(s.constructor);  // Outputs: Number() { [native code] } 
console.log(s instanceof String); // Outputs: false
console.log(s instanceof Object); // Outputs: false
//console.log(toString() in s);   
console.log(s.isPrototypeOf(Object)); // Outputs: false
//console.log(s.prototype.isPrototypeOf(Object));

console.log(s.hasOwnProperty ("toString")); // Outputs: false

console.log(s.toString()); // // Outputs: 12
// My Question is how does toString() function is been called, where does it falls int the prototype chain. Why is it not showing undefined.

console.log(s1.constructor); // Outputs: Number() { [native code] } 
console.log(s1 instanceof String); // Outputs: true

I understand that when we create an object by using {} or constructor (new String()) above, it inherits from Object.prototype. And thats why console.log(s1 instanceof String); // Outputs: true and thus we're able to call toString() on s1. But i'm confused with what happens in the case of var x = "someString" or var x = something.

Thanks for your time.

Upvotes: 0

Views: 36

Answers (1)

Pointy
Pointy

Reputation: 414046

There's a difference between string primitive values (like "hello world") and String objects. Primitive types — strings, numbers, booleans — are not objects.

When primitive values are used like objects, with the . or [] operators, the runtime implicitly wraps the values in objects via the corresponding constructors (String, Number, Boolean). Primitive values don't have properties, but because of that automatic wrapping you can do things like

var n = "hello world".length;

and it works.

Upvotes: 1

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