Reputation: 3
Assume I have three matrices...
A=matrix(c("a",1,2),nrow=1,ncol=3)
B=matrix(c("b","c",3,4,5,6),nrow=2,ncol=3)
C=matrix(c("d","e","f",7,8,9,10,11,12),nrow=3,ncol=3)
I want to find all possible combinations of column 1 (characters or names) while summing up columns 2 and 3. The result would be a single matrix with length equal to the total number of possible combinations, in this case 6. The result would look like the following matrix...
Result <- matrix(c("abd","abe","abf","acd","ace","acf",11,12,13,12,13,14,17,18,19,18,19,20),nrow=6,ncol=3)
I do not know how to add a table in to this question, otherwise I would show it more descriptively. Thank you in advance.
Upvotes: 0
Views: 1246
Reputation: 24490
You are mixing character
and numeric
values in a matrix and this will coerce all elements to character
. Much better to define your matrix as numeric and keep the character
values as the row names:
A <- matrix(c(1,2),nrow=1,dimnames=list("a",NULL))
B <- matrix(c(3,4,5,6),nrow=2,dimnames=list(c("b","c"),NULL))
C <- matrix(c(7,8,9,10,11,12),nrow=3,dimnames=list(c("d","e","f"),NULL))
#put all the matrices in a list
mlist<-list(A,B,C)
Then we use some Map
, Reduce
and lapply
magic:
res <- Reduce("+",Map(function(x,y) y[x,],
expand.grid(lapply(mlist,function(x) seq_len(nrow(x)))),
mlist))
Finally, we build the rownames
rownames(res)<-do.call(paste0,expand.grid(lapply(mlist,rownames)))
# [,1] [,2]
#abd 11 17
#acd 12 18
#abe 12 18
#ace 13 19
#abf 13 19
#acf 14 20
Upvotes: 2