CODEWITHSUNDEEP
scala
user2675516
user2675516

Reputation:

How to convert a 64bit hex number to binary in Scala?

I want to convert the following hash "d41d8cd98f00b204e9800998ecf8427e" to binary string. However, I can't seem to find a way to do that? Can someone teach me how I can do it in Scala? Thanks

Upvotes: 1

Views: 3766

Answers (1)

DaoWen
DaoWen

Reputation: 33019

Use BigInt:

scala> BigInt("d41d8cd98f00b204e9800998ecf8427e", 16).toString(2)
res0: String = 11010100000111011000110011011001100011110000000010110010000001001110100110000000000010011001100011101100111110000100001001111110

The 16 above means the string should be parsed in hex (base 16), and the 2 means the output string should be in binary (base 2).

If you want to dump the raw binary out to a file, you can convert the BigInt to a byte array and dump that:

scala> BigInt("d41d8cd98f00b204e9800998ecf8427e", 16).toByteArray
res1: Array[Byte] = Array(0, -44, 29, -116, -39, -113, 0, -78, 4, -23, -128, 9, -104, -20, -8, 66, 126)

Note that this gives you back 17 bytes instead of the 16 you'd expect for a 128-bit hash. That's because BigInt is a signed value, so it pads the byte array with an extra 0 in the most-significant-byte place to keep the value from being interpreted as negative. You could use res1.takeRight(16) to grab only the 16 bytes you're probably interested in.

Upvotes: 6

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