CODEWITHSUNDEEP
pythondictionary
fear_matrix
fear_matrix

Reputation: 4960

Comparing values in two list and updating it into the dictionary

I have a dictionary with below values, which consists airline code and their perror number. 

peq = {
  'sg':{'code':9, 'perror':0},
  '6e':{'code':17, 'perror':0},
  'g8':{'code':25, 'perror':0},
  'i7':{'code':33, 'perror':0},
  '9h':{'code':41, 'perror':0},
  'it':{'code':49, 'perror':0},
  'ic':{'code':57, 'perror':0},
  '9w':{'code':65, 'perror':0},
  's2':{'code':73, 'perror':0},
  'ai':{'code':81, 'perror':0}
}

I have a variable which is shown below. perrors consists of error code and acode is the airlines code similar to the one which is mentioned above in peq dictionary

perrors = ['0', '281', '2', '16', '0', '0', '2', '0', '0', '1']
acode = [41, 65, 17, 81, 73, 57, 9, 49, 33, 25]

I have then zipped the above two list in dictionary

>>> ic = dict(zip(acode,perrors))
>>> ic
{65: '281', 25: '1', 49: '0', 81: '16', 41: '0', 17: '2', 9: '2', 73: '0', 57: '0', 33: '0'}
>>>

Now what I am actually trying to solve is to update perror mentioned in the peq dictionary by comparing the ic code (on the left) with the value in the right in peq "perror".

Sorry if i am not being clear but in a nutshell I want to update all the values of perror mentioned in the peq dictionary with the values on its right mentioned in the ic dictionary but first it needs to do comparison whether the code exist in peq and if it does then update its perror (peq dictionary) with ic value.

Upvotes: 0

Views: 64

Answers (1)

Kobi K
Kobi K

Reputation: 7931

You need to iterate the dict and use the proper key from the zipped list:

import pprint

peq = {
'sg':{'code':9, 'perror':0},
'6e':{'code':17, 'perror':0},
'g8':{'code':25, 'perror':0},
'i7':{'code':33, 'perror':0},
'9h':{'code':41, 'perror':0},
'it':{'code':49, 'perror':0},
'ic':{'code':57, 'perror':0},
'9w':{'code':65, 'perror':0},
's2':{'code':73, 'perror':0},
'ai':{'code':81, 'perror':0}
}

perrors = ['0', '281', '2', '16', '0', '0', '2', '0', '0', '1']
acode = [41, 65, 17, 81, 73, 57, 9, 49, 33, 25]    
ic = dict(zip(acode,perrors))

for k, v in peq.items():
    try:
        v['perror'] = ic[v['code']]
    except KeyError:
        print 'failed to find code {} at ic zip'.format(v['code'])

pprint.pprint(peq)

Output:

{'6e': {'code': 17, 'perror': '2'},
 '9h': {'code': 41, 'perror': '0'},
 '9w': {'code': 65, 'perror': '281'},
 'ai': {'code': 81, 'perror': '16'},
 'g8': {'code': 25, 'perror': '1'},
 'i7': {'code': 33, 'perror': '0'},
 'ic': {'code': 57, 'perror': '0'},
 'it': {'code': 49, 'perror': '0'},
 's2': {'code': 73, 'perror': '0'},
 'sg': {'code': 9, 'perror': '2'}}

Upvotes: 1

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