CODEWITHSUNDEEP
stringpython-2.7
Joyce
Joyce

Reputation: 1

find the index of a letter in a string in python

I tried to print the index of every i in the word Mississippi. I've got the result but the print statement is repeating 3 times. This is the code 

s="Mississippi"
start=0
while start<len(s):  
     print "the index of i is: ", s.find('i',start,len(s))
     start=start+1

Upvotes: 0

Views: 9028

Answers (4)

Veera V S Bhargav Nunna
Veera V S Bhargav Nunna

Reputation: 3

import re
s="Wisconsin"
for c in re.finditer('i',s):
    print c.start(0)

Upvotes: 0

devale
devale

Reputation: 51

do you want to print the indexes as a list? try this:

l = []
for index, char in enumerate('mississippi'):
    if char == 'i':
        l.append(index)
print "the index of i is: ", l

the result will be:

the index of i is: [1, 4, 7, 10]

Upvotes: 1

Carsten
Carsten

Reputation: 1

Because of the while loop, you print the last found position of "i" in each run.

I would prefer a for loop over the string:

s="Misssssissippi"
start=0
character="i"

for i in s:
        if (i == character):
                print "the index of i is: ", start
        start=start+1

Upvotes: 0

Joshua Grigonis
Joshua Grigonis

Reputation: 768

If you use enumerate then you iterate through the string, looking at each letter and idx is counting upwards as you go.

for idx, letter in enumerate(s):
    if letter == "i":
        print "the index of i is: ", idx

Upvotes: 2

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