CODEWITHSUNDEEP
pythonregexformatstring-formattingmask
dot.Py
dot.Py

Reputation: 5157

How can I mask my float number, preferably without using regex?

How can I format a float number to string, by using a mask?

(I'm not proficient in regex, but if someone knows an one-line solution, why not?)

Here is my problem:

I have a float number like "6.88" and I need to format it using the following mask "00000000000.00"

6.88 = "00000000006.88"

14.3 = "00000000014.30"

00.0 = "00000000000.00"

I've already read the following post but I couldn't understood it:

Format number number with specific mask regex python

Example of my data:

6.88  => 00000000006.88
56.62 => 00000000056.62
9.58  => 00000000009.58
24.75 => 00000000024.75
14.30 => 00000000014.30

My not so efficient nor fast solution:

  1. convert from float to str
  2. split my string using the separator "."
  3. count chars before and after "."
  4. adapt my split[0] and split[1] to the mask, by using the length of these parameters
  5. done

Is there an easier way to do this?

Upvotes: 1

Views: 2257

Answers (2)

CristiFati
CristiFati

Reputation: 41137

Another example based on string formatting (not very nice or error prone):

def format_float(string_format, number):
    _int, _frac = string_format.split(".")
    real_format = "%%%s%d.%df" % ("0", len(_int) + len(_frac) + 1, len(_frac))
    return real_format % number

print format_float("00000.000", 1.2)

would yield: 00001.200

Upvotes: -1

vaultah
vaultah

Reputation: 46563

You'd use string formatting:

In [21]: '{:014.2f}'.format(6.88)
Out[21]: '00000000006.88'

In [22]: '{:014.2f}'.format(14.30)
Out[22]: '00000000014.30'

In [23]: '{:014.2f}'.format(0)
Out[23]: '00000000000.00'

According to 6.1.3.1. Format Specification Mini-Language,

  • 0 is the fill character

  • .2 sets the precision to 2

  • 14 is the width of the result string

Upvotes: 5

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