CODEWITHSUNDEEP
sortingfloating-pointmips
schaustm
schaustm

Reputation: 1

Sorting Floating Point Numbers In MIPS

We are given a project in which we have to find the min, max, and median of entered floating point numbers in MIPS. I'm currently trying to sort the numbers in ascending order but am not having much luck. I'm stuck on an error that says address out of range. Here is my code, can anyone help?

.data
 arr: .word 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,0
 end: .float 0.0
 low: .float 0

pro:  .asciiz "This Program will show the max, min,\nand median of the entered values.\nType 0.0 to end the program."
pro1: .asciiz "\nEnter a floating point value.\n"        

.text
li $v0, 4
la $a0, pro
syscall

index:
li   $s0,  0
li   $t0,  0
lwc1 $f11, end

main:
li $v0, 4
la $a0, pro1
syscall
li $v0, 6
syscall
la     $s0, arr
sw     $v0, arr
add    $s0, $s0, 4
c.eq.s $f0, $f11

loop1:
swc1   $f0, arr($s0)
addi   $s0, $s0, 4
swc1   $f1, arr($s0)
c.lt.s $f0, $f1
bc1t   min
j      main

min:
swc1 $f0, low
j    main

li $v0, 2
syscall

exit:
lwc1 $f12, low
li   $v0,  2
syscall
li   $v0, 10
syscall

Upvotes: 0

Views: 1080

Answers (1)

Scott Hunter
Scott Hunter

Reputation: 49893

You are loading the address of arr into $s0, but then using $s0 as an offset from arr (arr($s0)). If $s0 has the address of the data you want, just use ($s0).

Upvotes: 1

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