CODEWITHSUNDEEP
javastring
Mahesha999
Mahesha999

Reputation: 24871

Ensuring string having \n in it ends with particular string

I get a string which I have to check if it ends with SUCCESS. The string I get is multi-line, that is, it has \n in it. If it ends with SUCCESS., I have to return true, and if it ends with FAILED., I have to return false. However 

pValidationReport.endsWith("SUCCESS.")

evaluates to false even when the pValidationReport ends with FAILED. as can be seen below:

enter image description here

The method is as follows:

private boolean isValidationSuccess(String pValidationReport)
{
    if(pValidationReport.endsWith("SUCCESS."))
        return true;
    else if(pValidationReport.endsWith("FAILED."))
        return false;
}

What I am missing?

Upvotes: 2

Views: 116

Answers (2)

Zia
Zia

Reputation: 1011

first trim the string then chcek for endsWith()

pValidationReport.trim().endsWith("SUCCESS.")

The Java String Trim method is an instance method that is use to remove extra spaces from the start and end of a string. The String Trim method is used on the string object or literal. In Java, Strings are immutable, so once they are created, the content cannot be modified. Due to this reason, the result will be a newly created string object with no spaces at both ends of a string. it is evident that after trimming the string, it returns a new string object. When there is no space to trim at both sides, the same object of type String will be returned instead of a new one.

This endsWith() method returns a true if the character sequence represented by the argument is a suffix of the character sequence represented by this object, else false.

Upvotes: 2

ragelh
ragelh

Reputation: 165

If your input string has whitespace characters after the substring you're seeking for, it won't match. You could possibly use the regex for the purpose:

private boolean isValidationSuccess(String pValidationReport)
{
   Pattern successPattern = Pattern.compile(".*SUCCESS\\.\\s*$");
   return successPattern.matcher(pValidationReport).matches();
}

The \s* ensures that the SUCCESS. string at the end will be recognized even if followed by any arbitrary number of spaces, tabs, newlines, carriage-returns, form-feeds and vertical-tabs. It is also possible to move the Pattern to a final instance variable and then just use the matcher in your method, saving the call to compile():

private final Pattern successPattern = Pattern.compile(".*SUCCESS\\.\\s*$");

private boolean isValidationSuccess(String pValidationReport)
{
       return this.successPattern.matcher(pValidationReport).matches();
}

Upvotes: 1

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