CODEWITHSUNDEEP
c#
Jimmy Hopkins
Jimmy Hopkins

Reputation: 1

Copying Selected file from OpenFileDialog c#

I'm trying to copy a file from OpenFileDialog to a file path And I'm still a basic so it's hard for me. I google stuffs too but I dont understand that much. Can someone please help me out 

private void button2_Click(object sender, EventArgs e)
    {
        // Show the dialog and get result.
        DialogResult result = openFileDialog1.ShowDialog();
        if (result == DialogResult.OK) // Test result.
        {
            string newPath = @"C:\Users\" + un + "\\AppData\\Roaming\\NF";
            File.SetAttributes(newPath, FileAttributes.Normal);
            File.Copy(openFileDialog1.FileName, newPath, true);
        }
    }

Upvotes: 0

Views: 2125

Answers (1)

Steve
Steve

Reputation: 216293

The second argument of File.Copy is the name of the file in the new path.
You are passing a directory name.

Add this to your code before copying 

string destFile = Path.Combine(newPath, Path.GetFileName(openFileDialog1.FileName));
File.Copy(openFileDialog1.FileName, destFile, true);

Apart from this I recommend to not build your paths using string concatenations. This could be easily a source of errors. Use always the methods available in the class Path

string newPath = Path.Combine("C:\\Users",  un, "AppData\\Roaming\\NF");

Upvotes: 4

Related Questions