Reputation: 696
I am trying to get the password of a specified username, assign it to a PHP variable, and then print it. Here's the code for it -
$user = $_POST["uname"];
$pass = mysqli_query($con, "SELECT pass FROM users WHERE username = '$user'");
$result = mysqli_fetch_array($pass);
$specific = $result['pass'];
echo $specific;
The problem is that nothing is being printed at all! Even no error. What do I do?
Upvotes: 0
Views: 2432
Reputation: 870
Escape your values and check for errors:
$user = mysqli_escape_string( $con, $_POST["uname"] );
$pass = mysqli_query( $con, "SELECT pass FROM users WHERE username = '$user'");
# Error checking
if( $pass === false ) {
echo 'Error: ', mysqli_error( $con );
}
# Check for no user with that password
if( mysqli_num_rows( $pass ) == 0 ) {
echo 'No user with that username.';
}
# Use as associate arary
$result = mysqli_fetch_assoc($pass);
$specific = $result['pass'];
echo $specific;
edit: Added check for no results.
Upvotes: 1
Reputation:
$pass = mysqli_query($con, "SELECT pass FROM users WHERE username = '$user'") or die(mysqli_error($con));
This will Show you the Correct Error in your query
Upvotes: 1