Reputation: 854
I am trying convert two std_logic bits to an integer as follows
LIBRARY IEEE;
USE IEEE.std_logic_1164.ALL;
USE IEEE.numeric_std.ALL;
ENTITY TEST IS
PORT (sw1, sw0 : IN std_logic;
x : OUT integer RANGE 3 DOWNTO 0);
END ENTITY TEST;
ARCHITECTURE dflow OF TEST IS
SIGNAL mes_sel : integer RANGE 3 DOWNTO 0;
BEGIN
mes_sel <= to_integer(unsigned(std_logic_vector(SW1 & SW0)));
x <= mes_sel;
END ARCHITECTURE dflow;
but the compiler does not like the mes_sel assignment. I get the following compiler error message:
Error (10327): VHDL error at Q4.vhd(92): can't determine definition of operator ""&"" -- found 4 possible definitions
Can I not concatenate 2 bit of std_logic to a vector and then convert? Or is it something else? regards D
Upvotes: 3
Views: 3154
Reputation:
The error message tells you roughly what's wrong, and it's not a problem with the assignment.
GHDL gives a better diagnosis:
ghdl -a test.vhd
test.vhd:13:57: can't resolve overload for operator "&"
test.vhd:13:57: possible interpretations are:
../../src/ieee/numeric_std.v93:66:18: array type "signed"
../../src/ieee/numeric_std.v93:65:20: array type "unsigned"
../../src/ieee/std_logic_1164.v93:69:30: array type "std_logic_vector"
../../src/ieee/std_logic_1164.v93:54:31: array type "std_ulogic_vector"
ghdl: compilation error
VHDL allows overloaded operators, distinguishable by the types of their arguments (in this case, std_logic) and their return types, (in this case ... well... what?)
There are apparently 4 types which have a std_logic_vector()
type conversion function declared on them, as well as a &
operator taking two std_logic arguments; and ghdl (unlike whatever tool you're using) helpfully lists them.
In such cases, VHDL (unlike some other languages) insists that you pick one, rather than arbitrarily making a hidden (and possibly wrong) choice for you.
You can do this with a type mark. As you actually want an unsigned
, the obvious choice is unsigned'()
(note the "'" symbol, also used for attributes).
mes_sel <= to_integer(unsigned'(SW1 & SW0));
Note that if VHDL allowed anything simpler, like to_integer(SW1 & SW0)
it would be positively dangerous as there is nothing to distinguish between signed and unsigned conversions, making the conversion at least non-obvious, and quite possibly wrong.
Upvotes: 6