CODEWITHSUNDEEP
phparraysechovar-dump
ctrlmaniac
ctrlmaniac

Reputation: 444

Unable to access associative array values

I have two config files. The first, which is called configs.php contains an array with some values:

$welcomeConfigs = [
  "title" => "welcome",
  "description" => "a description"
];

The second file includes the configs.php one and use the its array to generate some other variables. The second file is called views.php.

$viewConfigs = VIEW . 'Configs';
$pathToViewConfigs = VIEW . '/configs.php';

include($pathToViewConfigs);

var_dump($$viewConfigs);

In index.php:

define("VIEW", "welcome");
include('views.php');

I need to store in the $title variable, for example, the value of the associative array, but when I try to do it nothing happens. I tried to use var_dump to check if the syntax was correct and I used en external fiddle to check if something was wrong, but nothing is actually wrong.

When type var_dump($$viewConfigs); the output is { ["title"]=> string(7) "welcome" ["description"]=> string(13) "a description" }

but when I type var_dump($$viewConfigs['title']); the output is NULL.

How can I fix this? What I am doing wrong?

Upvotes: 2

Views: 63

Answers (1)

fusion3k
fusion3k

Reputation: 11689

You have to use this syntax:

var_dump( ${$viewConfigs}['title'] );

that interpret $viewConfigs as variable name. The form $$viewConfigs['title'] interpret as variable name the content od $viewConfigs['title'], that not exists.

I hope I have been clear.

(Edit:) See more about variable variables on PHP Official site

Upvotes: 2

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