Reputation: 94
I have an array like this one:
array (size=1)
0 =>
array (size=33)
0 => int 126
1 => int 43
2 => int 4
3 => int 0
4 => int 3
5 => int 3
6 => int 30
7 => int 15
8 => int 22
9 => int 27
10 => int 22
11 => int 46
12 => int 0
13 => int 8
14 => int 14
15 => int 8
array (size=1)
1 =>
array (size=33)
0 => int 273
1 => int 3
2 => int 4
3 => int 28
4 => int 36
5 => int 19
6 => int 142
7 => int 81
8 => int 59
9 => int 71
10 => int 88
11 => int 47
12 => int 42
13 => int 0
14 => int 12
15 => int 97
(of course it is way longer) and I need both to sum all the value with the same key and count how many values with the same key are >0 (cause I have to find the avarage of all the numbers >0
My expected result is
0=>
'sum' => 399
'count'=>2
1=>
'sum' =>46
'count'=>2
how can I create this array?
Upvotes: 0
Views: 700
Reputation: 1466
There's an inbuilt function in PHP to count the sum of all the elements of an array. Here, this will give you your expected output :
<?php
$arr = [[10, 20, 30, 40], [10, 20, 30], [10, 20, 30, 4]];
// Let the magic happen...
$yourArray = array_map(function ($el){ return ["sum" => array_sum($el), "count" => count($el)]; }, $arr);
print_r($yourArray);
?>
Upvotes: 1
Reputation:
I have thought about this, and came up with a solution (I think...), it comes in the form of a function and it goes like this:
function getSumAndCount(array $arr)
{
$sum = 0;
$count = 0;
foreach ($arr as $v)
{
$count++;
if (is_array($v))
{
$next = getSumAndCount($v);
$count += $next['count'];
$sum += $next['sum'];
}
else
{
!is_numeric($v) ?: $sum += $v;
}
}
return [ 'sum' => $sum, 'count' => $count ];
}
It has a recursive check to if the array is multidimensional, checks if the value is numeric and sets the count and sum in a return array.
I haven't tested this properly as yet, but please test and let me know if you get the desired output.
EDIT
I will extend this to count dupe keys soon
Upvotes: 0