CODEWITHSUNDEEP
php
j8d
j8d

Reputation: 520

Else Statement in PHP

I'm learning PHP and wrote a simple translator. 

<!DOCTYPE html>
<html lang="en">
<head>
	<meta charset="UTF-8">
	<title>Translator</title>
</head>
<body>

<form method="post" action="">
<input type="string" name="word">
<input type="submit">	
</form>

<?php 

if (isset($_POST["word"])) {
	$word = $_POST["word"];
	echo $word . " -> ";

function translate($word){
$dict = array('hello' => 'sawadee khap','thanks' => 'kap khum khap','sorry' => 'mai pen rai');
	foreach ($dict as $en => $th) {
		if ($word == $en) {
			echo $th;
			break;
		}
	}
} 

translate($word);

} else {
	echo "enter a word";
}

?>
</body>
</html>

How can I display the string 'not in dictionary' when I enter a word that isn't in the array? I'd also appreciate any feedback or suggestions on improving the code.

Upvotes: 0

Views: 67

Answers (6)

dhi_m
dhi_m

Reputation: 1265

Please try this

<form method="post" action="">
    <input type="string" name="word">
    <input type="submit">   
</form>

<?php

function translate($word) {
    $dict = array('hello' => 'sawadee khap', 'thanks' => 'kap khum khap', 'sorry' => 'mai pen rai');

    if (array_key_exists($word, $dict)) {
       echo $dict[$word];

    } else {
        echo " not in dictionary";
    }
}

if (isset($_POST["word"])) {
    $word = $_POST["word"];
    echo $word . " -> ";
    translate($word);
} else {
    echo "enter a word";
}
?>

Upvotes: 0

Nijraj Gelani
Nijraj Gelani

Reputation: 1466

PHP has a function for this, called in_array. You can do something like this :

$dict = array('hello' => 'sawadee khap','thanks' => 'kap khum khap','sorry' => 'mai pen rai');
if(!in_array($word, array_keys($dict))){
    echo '"' . $word . '" not found in the dictionary.';
}else{
    echo $dict[$word];
}

Edit: Improved

$dict = array('hello' => 'sawadee khap','thanks' => 'kap khum khap','sorry' => 'mai pen rai');
if(!array_key_exists(strtolower($word), $dict)){
    echo '"' . $word . '" not found in the dictionary.';
}else{
    echo $dict[$word];
}

Upvotes: 3

betchern0t
betchern0t

Reputation: 73

Your top if statement is missing a brace.

As to your question, I assume that you are wanting to walk through the dictionary and if the word isn't found to echo it. You could use a flag. Set it to something before the for loop and then when you find the word set it to something else. Then check at the end of the for loop eg:

$found = false;
foreach ($dict as $en => $th) {
    if ($word == $en) {
        $found = true'
        echo $th;
        break;
    }
}
if (!$found) echo $word;''

Upvotes: -1

m.qadhavi
m.qadhavi

Reputation: 84

you can use array_key_exist :

$dict = array('hello' => 'sawadee khap','thanks' => 'kap khum khap','sorry' => 'mai pen rai');
if (array_key_exists($word, $dict)) {
//in dictionary
}else{
//not in dictionary
}

Upvotes: 1

Professor Abronsius
Professor Abronsius

Reputation: 33813

If you return a value from the function when a word is found or falsoe otherwise you can do a logical test on the result to display the alternative error message.

<form method="post" action="">
    <input type="string" name="word">
    <input type="submit">   
</form>
<?php 
    if( $_SERVER['REQUEST_METHOD']=='POST' ){
        if ( isset( $_POST["word"] ) ) {

            $word = $_POST["word"];
            echo $word . " -> ";

            function translate( $word=false ){
                if( $word ){
                    $dict = array('hello' => 'sawadee khap','thanks' => 'kap khum khap','sorry' => 'mai pen rai');
                    foreach ($dict as $en => $th) {
                        if( $word == $en ) {
                            return $th;
                        }
                    }
                }
                return false;
            } 

            $result=translate( $word );
            echo $result ? $result : 'Sorry, not found!';

        } else {
            echo "enter a word";
        }
    }
?>

Upvotes: 1

Md. Sahadat Hossain
Md. Sahadat Hossain

Reputation: 3236

Change your function code

function translate($word){
$dict = array('hello' => 'sawadee khap','thanks' => 'kap khum khap','sorry' => 'mai pen rai');

if(array_key_exists($word, $dict)){
     echo $dict[$word];
}else{
    echo 'not in dictionary';
}
}

Upvotes: 2

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