CODEWITHSUNDEEP
javaandroidstringsubstring
LS_
LS_

Reputation: 7139

Trying to get first character from a string with multiple words where the first can be an Emoji (Android)

I need to get the first character of a string, currently what I'm using is:

String firstCharacter = getTitle().substring(0, 1);

where getTitle() returns a String that can contain multiple words and also emojis, if the first character is an emoji and I use substring when I display firstCharacter instead of the emoji I get a question mark because using substring I cut the emoji characters.

What I want to do is:

How can I possibly do it?

Upvotes: 2

Views: 1610

Answers (3)

Synthesis
Synthesis

Reputation: 554

Kotlin Multiplatform (KMP) version which supports Emojis, as well as other multibyte strings

// libs used:
implementation("de.cketti.unicode:kotlin-codepoints-deluxe:0.9.0") // For KMP and to support some 4-byte strings afaict
implementation("org.kodein.emoji:emoji-kt:2.1.0")

/**
 * Multibyte (e.g. Chinese, emoji) safe way to fetch the first character of a string
 */
fun String.firstCharacter(): String {
    if (this.length < 2) return this

    EmojiFinder().findEmoji(this).firstOrNull()?.let {
        if (it.start == 0) return this.substring(it.start, it.end)
    }

    return this.take(this.offsetByCodePoints(0, 1))
}

@Test
fun testFirstCharater() {
    assertEquals("", "".firstCharacter())
    assertEquals("1", "1".firstCharacter())
    assertEquals("J", "Johny".firstCharacter())

    assertEquals("\uD83D\uDE0A", "\uD83D\uDE0A Regular emoji".firstCharacter())
    assertEquals("\uD83C\uDDEB\uD83C\uDDF7", "\uD83C\uDDEB\uD83C\uDDF7 flag".firstCharacter())
    assertEquals(
        "\uD83E\uDD26\uD83C\uDFFC\u200D♂\uFE0F", 
        "\uD83E\uDD26\uD83C\uDFFC\u200D♂\uFE0F facepalman".firstCharacter()
    )

    assertEquals("读", "读写".firstCharacter())
    assertEquals("中", "中文".firstCharacter())
    assertEquals("ض", "ضط arabic".firstCharacter())
    assertEquals("ਆ", "ਆ 3 bytes".firstCharacter())
    assertEquals("\uD808\uDC16", "\uD808\uDC16 4 byte char".firstCharacter())
}

Upvotes: 1

OlegKrikun
OlegKrikun

Reputation: 644

Just use String.codePointAt() 

new String(Character.toChars(getTitle().codePointAt(0)))

Upvotes: 2

yennsarah
yennsarah

Reputation: 5517

Android now supports Emojis with EmojiCompat

EmojiCompat is used to support Emojis in Android. You can initialize it by downloading it or packaging it within your app.


// Initialize with your desired config 
EmojiCompat.init(BundledEmojiCompatConfig(context))

// Check if EmojiCompat was successfully loaded
if (EmojiCompat.get().loadState == EmojiCompat.LOAD_STATE_SUCCEEDED) {
    EmojiCompat.get().hasEmojiGlyph(yourString)
}

Old Answer:

Emojis range can be found here

So, this would result in (not tested):

if(getTitle().substring(0,5)
    == ("/[\u2190-\u21FF] | [\u2600-\u26FF] | [\u2700-\u27BF] | 
          [\u3000-\u303F] | [\u1F300-\u1F64F] | [\u1F680-\u1F6FF]/g")){
    firstCharacter = getTitle().substring(0,5);
} else{
    firstCharacter = getTitle().substring(0,1);
}

Upvotes: 1

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