Reputation: 173
Working on a project using CMake. This project contains an executable and a python script. These two files should be compiled/copied in the same directory at build.
I try something like :
add_executable( ${myTarget} ${all_c_sources} )
add_custom_command(
TARGET ${myTarget} POST_BUILD
COMMAND ${CMAKE_COMMAND} -E copy ${pythonScriptPath} ${RUNTIME_OUTPUT_DIRECTORY}/
)
The executable is well build in a default location like ${CMAKE_BINARY_DIR}/Debug but the copy of the python script failed :
c:\Program Files (x86)\CMake\bin\cmake.exe" -E copy C:/.../script.py /\r
My goal is to use CMake default behavior as mush as possible. Is there a simple way to get the default output path ?
Thanks !
Upvotes: 2
Views: 1270
Reputation: 1697
Something like this:
add_custom_command(TARGET ${LIBRARY_NAME} POST_BUILD
COMMAND ${CMAKE_COMMAND} -E copy_if_different
$<TARGET_FILE:${LIBRARY_NAME}>
$<TARGET_FILE_DIR:${CMAKE_PROJECT_NAME}>/path/to/where/module/should/be
COMMENT "Copying file to Runtime directory: " $<TARGET_FILE:${LIBRARY_NAME}>
)
Adjust it to your needs.
Read about CMake Generator Expressions if you need to know more.
Upvotes: 1