CODEWITHSUNDEEP
python-2.7dictionary
Vijay
Vijay

Reputation: 111

sorting of python dict, first by value then by key

I want to sort a dict, first by the value and then by the key. The key being a string.

Example,

>>> words = {'fall':4, 'down':4, 'was':3, 'a':3, 'zebra':2, 'bitter':1, 'betty':1}
>>> sorted(words.items(), key=itemgetter(1,0), reverse=True)
[('fall', 4), ('down', 4), ('was', 3), ('a', 3), ('zebra', 2), ('bitter', 1), ('betty', 1)]

As you can see above, the dict is getting sorted by value but not by the key.

Thanks.

Edit: I forgot to point out that I wanted the values to get sorted top to down and the key bottom to top.

Upvotes: 0

Views: 860

Answers (1)

Kordi
Kordi

Reputation: 2465

This should do the trick. Take advantage of the fact that the values are numbers.

from operator import itemgetter

words = {'fall':4, 'down':4, 'was':3, 'a':3, 'zebra':2, 'bitter':1, 'betty':1}
sorted_words = [v for v in sorted(words.iteritems(), key=lambda(k, v): (-v, k))]
print(sorted_words)

Output:

[('down', 4), ('fall', 4), ('a', 3), ('was', 3), ('zebra', 2), ('betty', 1), ('bitter', 1)]

Upvotes: 2

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