CODEWITHSUNDEEP
phphtml
Freddy
Freddy

Reputation: 867

Calculating age from Day, Month, Year chosen from drop down list

I have a in which my DOB is registered depending on the selection in a drop down list. 

 Date of Birth:
    <select name="DOBDay" required>
    <option> Day </option>
    <option value="1">1</option>
    <option value="2">2</option>
    // etc ....

The same approach is adopted for month and year. As a result of this, when I process the registration form, data is obtained from these three dropdowns and are assigned to three different variables:

$DOBDay       = strip_tags(@$_POST['DOBDay']);
$DOBMonth     = strip_tags(@$_POST['DOBMonth']);
$DOBYear      = strip_tags(@$_POST['DOBYear']);

I need a way I can get the current age of the user based on the DOB provided, but since I have it stored in three different variables (and three different columns in my database), I don't know how I can get their current age. Any ideas?

More details:

I need an $age variable which will calculate the age and I need it to be of type int, so that I can store the age in the age column in my db.

Upvotes: 1

Views: 489

Answers (2)

bytesized
bytesized

Reputation: 1522

How about this:

$birthday = new DateTime();
$birthday->setDate($DOBYear, $DOBMonth, $DOBDay);
$now = new DateTime("now");
$age = $birthday->diff($now);
echo $age->y . " years old";

Upvotes: 1

McCormick32
McCormick32

Reputation: 185

Take your strings and concatenate them into a date format and use code similar to this.

<?php
  //date in mm/dd/yyyy format; or it can be in other formats as well
  $birthDate = "$DoBMonth/$DoBDay/$DoBYear";
  //explode the date to get month, day and year
  $birthDate = explode("/", $birthDate);
  //get age from date or birthdate
  $age = (date("md", date("U", mktime(0, 0, 0, $birthDate[0], $birthDate[1], $birthDate[2]))) > date("md")
    ? ((date("Y") - $birthDate[2]) - 1)
    : (date("Y") - $birthDate[2]));
  echo "Age is:" . $age;
?>

Upvotes: 0

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