CODEWITHSUNDEEP
bash
evobe
evobe

Reputation: 71

In bash, my for loop returns too many results

so I'm trying to compare user lists in bash, file vault enabled users vs users I've defined. As a test I ran:

for i in "$ulist"; do
  if ($i == *testuser*) || ($i == *otheruser*)
  then
    echo "dont' change $i"
  else
    echo "change $i"
  fi
done

but it only returns

testuser
otheruser
x
y
change z

for the record:

ulist=$(fdesetup list | cut -d',' -f1)

any idea why it just cycles through the whole list without really comparing it the way I want it to? In the end I want to be able to skip modifying the users that I've told it skip.

Upvotes: 0

Views: 52

Answers (2)

evobe
evobe

Reputation: 71

Yeah, I'm very new to bash, but I found that it's very hard to compare an array against another array and produce what I want. I ended up just finding a way to only get the result I wanted without having to check through two arrays. I'm still having tons of other small issues but so far this hurdle has been crossed. I did end up using grep to find the user and awk to print just the first column I wanted. This was my first Stack post, thanks for the help all.

Upvotes: 0

tripleee
tripleee

Reputation: 189507

I guess what you actually want is something like

fdesetup list |
grep -vE '^(test|other)user,'

If you really want the verbose do/don't output, change the grep to a simple sed script which does that.

Upvotes: 1

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