CODEWITHSUNDEEP
python-3.x
SchoolHelp
SchoolHelp

Reputation: 25

How to read from a file without a gap?

So I have read/printed out 2 lines from a file but there is a gap in between them but I want to but both of them beside each other , how do I do that.

if GTIN == '86947367':
    fp = open("read_it.txt")
    for i, line in enumerate(fp):
        if i == 1:
            print(line)
        elif i == 2:
            print(line)
    fp.close()

When I run this it gives an output of:

banana
(space)
(space)
5.00

I wanna put both print(line)besides each other to give an output of:

banana 5.00

TEXT FILE:

86947367
banana
5.00

78364721
apple
3.00

35619833
orange
2.00

84716491
sweets
8.00

46389121
chicken
10.00

74937462

Upvotes: 0

Views: 94

Answers (2)

Mike Müller
Mike Müller

Reputation: 85442

This:

with open("read_it.txt") as fp:
    next(fp)
    print(next(fp).rstrip(), next(fp))

prints:

banana 5.00

First you open the file with promise to close it with open("read_it.txt") as fp:'. Now you use next(fp) to skip the first line. Finally, you print the content of both lines. You need to strip the newline character at the end of the first printed line with .rstrip().

Your file object fp is a so called iterator. That means next(fp) gives you the next line.

This would work, if you want to print the output for your GTIN:

with open("read_it.txt") as fp:
    GTIN = '86947367'
    show = False
    for line in fp:
        if not line.strip():
            show = False
            continue
        if line.strip() == GTIN:
            show = True
            continue
        if show:
            print(line.rstrip(), end=' ')

prints:

banana 5.00

Upvotes: 1

Grief
Grief

Reputation: 2040

with open("read_it.txt") as f: print(' '.join([f.readline().rstrip() for x in range(3)][1:]))

Upvotes: 0

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