CODEWITHSUNDEEP
linuxbashawk
user6069028
user6069028

Reputation:

Awk command file: How to accomplish this task

In awk there is toupper() to capitalize text and gsub() to replace text

I have seen examples of how to do each task on a file, and they work, however I am curious as to how to make a command file that when piplined with "who" will accomplish the following:

Instead of "who" outputting like such:

firstname.lastname pts/# .....[other information]

It will output like this:

Firstname, Lastname TTY #     [other information removed]

How can this task be accomplished in an awk command file please?

Upvotes: 0

Views: 58

Answers (2)

xvan
xvan

Reputation: 4855

There must be a cleaner way but this is my attempt.

echo "firstname.lastname pts/# .....[other information]" |
awk  'r=gensub(/([[:alnum:]]*)\.([[:alnum:]]*).*/, "\\1 \\2", "",$1),
split(r,a," ")
{ print toupper(substr(a[1],1,1)) substr(a[1], 2) " " toupper(substr(a[2],1,1)) substr(a[2], 2) " TTY#" }'

Upvotes: 1

karakfa
karakfa

Reputation: 67507

awk to the rescue!

for any field you can do this

awk '{print toupper(substr($1,1,1)) tolower(substr($1,2,length($1)-1))'

I'm not familiar with the firstname.lastname who format (I see userid instead).

Upvotes: 1

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