CODEWITHSUNDEEP
javascriptjqueryregex
dwinnbrown
dwinnbrown

Reputation: 4009

JS - Ignore numbers after decimal point

So I am trying to convert the .text() of a div into a number that can be used for some math within the JS (currency conversion). I am gathering the text content of a div which contains items such as currency symbols as well as a decimal point which is always followed by 00 For example if the div contained £35,000.00 I am trying to get it to return 35000 not 3500000.

I have got some RegExp that only allows use of numbers 1-9 and therefore removes the £ sign but it also takes the decimal point out, thus multiplying the number I want by 100.

This is my code:

var thisDiv = $(this);
var amount = $( this ).text().replace(/[^0-9]/gi, '');

Is there any way to ignore the numbers that come after the dot other than just dividing my variable by 100?

Upvotes: 0

Views: 1393

Answers (4)

jazeb007
jazeb007

Reputation: 668

no need to convert to string and split and get the 0 index just do .toFixed(); Like:

const num = 34.434343;
num.toFixed();

Upvotes: 0

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 626794

You can restrict what you match with [^0-9] using a (?!\.\d+$) negative lookahead:

/(?!\.\d+$)[^0-9]/g
 ^^^^^^^^^^

See the regex demo

The pattern means: match any non-digit if it is not a literal . followed with 1+ digit up to the end of the string.

var re = /(?!\.\d+$)[^0-9]/g; 
var str = '£35,000.00';
var result = str.replace(re, '');
document.body.innerHTML = result;

Upvotes: 0

aashah7
aashah7

Reputation: 2195

Extending on Mark's answer, you can the digits number before and after the decimal with the following:

numberString.toString().split(".")[0];   //before
numberString.toString().split(".")[1];   //after

Upvotes: 0

Mark Evaul
Mark Evaul

Reputation: 653

/[^0-9\.]/

this regex will keep 0-9 and .

However, it will also allow values like 1.2.3 (multiple dots)

if you want more validation than that, you might want to take a couple steps

var numberString = value.replace(/[^0-9\.]/gi, '');
if (isNaN(numberString )) {
   console.log('invalid');
} else {
   //parse number and use it
}

Upvotes: 3

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