CODEWITHSUNDEEP
rggplot2
jalapic
jalapic

Reputation: 14222

Nested facet_wrap() in ggplot2

Say I have these data:

set.seed(100)
mydf<-
data.frame(
day = rep(1:5, each=20),
id = rep(LETTERS[1:4],25),
x = runif(100),
y = sample(1:2,100,T)
)

If I just want to plot all five days of id=="A" using facet_wrap(), we do like this:

ggplot(mydf[mydf$id=="A",], aes(x,y))  +  
       geom_tile() +
       facet_wrap(~day,ncol=1)

Gives: enter image description here

But, if I want to plot four of these next to each other automatically in a 2x2 grid (i.e. showing A,B,C,D), is that possible using a nested facet? I tried doing multiple variables in the function like this:

ggplot(mydf, aes(x,y))  +  
  geom_tile() +
  facet_wrap(~ day+id)

but this gives this:

enter image description here

I'm looking for a nested approach. Five faceted rows by day in each panel with each plot in columns/rows by id. Obviously for a small number of plots I could save individually and arrange with grid.arrange etc., but in the real data I have many plots so want to automate if possible.

EDIT:

In response to comment - this is the sort of desired output:

enter image description here

Upvotes: 3

Views: 3985

Answers (2)

baptiste
baptiste

Reputation: 77124

try this,

p <- ggplot(mydf, aes(x,y))  +  
  geom_tile() +
  facet_wrap(~ day, ncol=1) 

library(plyr)
lp <- dlply(mydf, "id", function(d) p %+% d + ggtitle(unique(d$id)))
library(gridExtra)
grid.arrange(grobs=lp, ncol=2)

enter image description here

Upvotes: 3

missng
missng

Reputation: 199

Here is a quick attempt using the multiplot function found here

ids = levels(as.factor(mydf$id))
p = vector("list", length(ids))
names(p) = ids

for(i in 1:length(ids)){
  p[[i]] = ggplot(mydf[mydf$id == ids[i],], aes(x,y)) + geom_tile() + ggtitle(paste(ids[i])) + facet_wrap(~day, ncol=1)
}

multiplot(p$A, p$B, p$C, p$D, cols = 2)

enter image description here

Upvotes: 2

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