CODEWITHSUNDEEP
php
Starfire1337
Starfire1337

Reputation: 51

PHP detecting if a function has an optional argument

Suppose I have this class:

class Test
{
    public function foo($argument = "") {
        //do something
    }

    public function bar($argument) {
        //do something else
    }
}

Is there any way I can tell if foo's argument is optional, and bar's argument isn't through PHP?

I've tried using getParameters() from ReflectionMethod, but that just returns the name, and not any information that can tell me if it is optional or not.

Upvotes: 1

Views: 161

Answers (2)

Maciej Cygan
Maciej Cygan

Reputation: 5471

I am not entirely sure what you mean by detecting if function has optional argument.

But whats wrong with doing this ?

public function foo($argument = "") {
    if($argument != "") {
       .... argument is set
    }
}

Edit: I see what you mean now. Yes you can use reflections for that 

$reflection = new ReflectionMethod($className, $methodName);
$params = $reflection->getParameters();
foreach ($params as $param) {
    echo $param->getName();
    echo $param->isOptional();
}

Upvotes: 0

Scopey
Scopey

Reputation: 6319

With reflected methods getParameters will return an array of ReflectionParameters. You can check the isOptional method on ReflectionParameter.

When you echo or print a ReflectionParameter it will return its name.

Here's an example

Upvotes: 4

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