CODEWITHSUNDEEP
javascriptmomentjs
Miloš Đakonović
Miloš Đakonović

Reputation: 3871

Moment.js - two dates difference in number of days

I get incorrect results when trying to find numeric difference between two dates:

var startDate = moment( $('[name="date-start"]').val(), "DD.MM.YYYY"), // $('[name="date-start"]').val() === "13.04.2016"
endDate       = moment( $('[name="date-end"]'  ).val(), "DD.MM.YYYY"); // $('[name="date-end"]').val() === "28.04.2016"

var diff = startDate.diff(endDate);

console.log( moment(diff).format('E') );

Between 13.04.2016 and 28.04.2016 I shouldn't get that difference is 3 or 2 days...

I've tried to multiple combinations:

Result: all the time I get that difference is 3 or 2 days.

What am I doing wrong?

Upvotes: 80

Views: 199730

Answers (6)

Ranvijay Kumar Singh
Ranvijay Kumar Singh

Reputation: 579

Calculate the differance in Seconds

var date1 = moment("2022-10-30");
var date2 = moment("2022-12-30");
var diff = date1.diff(date2, 'seconds')

and then you can conver then in to hours and Minutes and seconds.

var mind = diff % (60 * 60);
const hours = Math.floor(diff / (60 * 60));
const minutes = Math.floor(mind / 60);
var seconds = Math.ceil(mind % 60);

Thanks

Upvotes: 0

Codemaker2015
Codemaker2015

Reputation: 15756

Use moment.js to find the difference between two dates in days.

Install moment.js using the following command,

npm install moment

Calculate the difference between two dates in days.

var moment = require('moment');

var date1 = moment("2022-10-30");
var date2 = moment("2022-12-30");
var days = date1.diff(date2, 'days')

Upvotes: 6

Harshit Singhai
Harshit Singhai

Reputation: 1288

const FindDate = (date, allDate) => {
        
    // moment().diff only works on moment(). Make sure both date and elements in allDate array are in moment format
    let nearestDate = -1; 
    
    allDate.some(d => {
        const currentDate = moment(d)
        const difference = currentDate.diff(d); // Or d.diff(date) depending on what you're trying to find
        if(difference >= 0){
            nearestDate = d
        }
    });
    
    console.log(nearestDate)
}

Upvotes: 0

Muneeb
Muneeb

Reputation: 1559

Here's how you can get the comprehensive full fledge difference of two dates.

 function diffYMDHMS(date1, date2) {

    let years = date1.diff(date2, 'year');
    date2.add(years, 'years');

    let months = date1.diff(date2, 'months');
    date2.add(months, 'months');

    let days = date1.diff(date2, 'days');
    date2.add(days, 'days');

    let hours = date1.diff(date2, 'hours');
    date2.add(hours, 'hours');

    let minutes = date1.diff(date2, 'minutes');
    date2.add(minutes, 'minutes');

    let seconds = date1.diff(date2, 'seconds');

    console.log(years + ' years ' + months + ' months ' + days + ' days ' + hours + ' 
    hours ' + minutes + ' minutes ' + seconds + ' seconds'); 

    return { years, months, days, hours, minutes, seconds};
}

Upvotes: 10

dubes
dubes

Reputation: 5524

From the moment.js docs: format('E') stands for day of week. thus your diff is being computed on which day of the week, which has to be between 1 and 7.

From the moment.js docs again, here is what they suggest: 

var a = moment([2007, 0, 29]);
var b = moment([2007, 0, 28]);
a.diff(b, 'days') // 1

Here is a JSFiddle for your particular case: 

$('#test').click(function() {
  var startDate = moment("13.04.2016", "DD.MM.YYYY");
  var endDate = moment("28.04.2016", "DD.MM.YYYY");

  var result = 'Diff: ' + endDate.diff(startDate, 'days');

  $('#result').html(result);
});
#test {
  width: 100px;
  height: 100px;
  background: #ffb;
  padding: 10px;
  border: 2px solid #999;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.12.0/moment.js"></script>

<div id='test'>Click Me!!!</div>
<div id='result'></div>

Upvotes: 149

VonD
VonD

Reputation: 5155

the diff method returns the difference in milliseconds. Instantiating moment(diff) isn't meaningful.

You can define a variable :

var dayInMilliseconds = 1000 * 60 * 60 * 24;

and then use it like so :

diff / dayInMilliseconds // --> 15

Edit

actually, this is built into the diff method, dubes' answer is better

Upvotes: 0

Related Questions