CODEWITHSUNDEEP
arraysnumpy
K.Ivi
K.Ivi

Reputation: 111

Replace zero array with new values one by one NumPy

I stuck with a simple question in NumPy. I have an array of zero values. Once I generate a new value I would like to add it one by one.

arr=array([0,0,0])
# something like this
l=[1,5,10]
for x in l:
     arr.append(x)   # from python logic

so I would like to add one by one x into array, so I would get: 1st iteration arr=([1,0,0]); 2d iteration arr=([1,5,0]); 3rd arr=([1,5,10]);

Basically I need to substitute zeros with new values one by one in NumPy (I am learning NumPy!!!!!!). I checked many of NumPy options like np.append (it adds to existing values new values), but can't find the right.

thank you

Upvotes: 1

Views: 857

Answers (1)

mtzl
mtzl

Reputation: 404

There are a few things to pick up with numpy:

  • you can generate the array full of zeros with 

    >>> np.zeros(3)
array([ 0.,  0.,  0.])

  • You can get/set array elements with indexing as with lists etc:

    arr[2] = 7

for i, val in enumerate([1, 5, 10]):
    arr[i] = val

  • Or, if you want to fill with array with something like a list, you can directly use:

    >>> np.array([1, 5, 10])
array([ 1,  5, 10])

  • Also, numpy's signature for appending stuff to an array is a bit different:

    arr = np.append(arr, 7)

Having said that, you should just consider diving into Numpy's own userguide.

Upvotes: 1

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