CODEWITHSUNDEEP
phpdatedatetime
Nevermore
Nevermore

Reputation: 882

How to get third previous month from inputted month-year?

I am trying to get third previous month from inputted month-year ie. if I give 06-2016 as an input, it should give me 03-2016 as result. I have tried strtotime("-3 Months"). But it gives me just 3 months from current date time.

Can someone tell me how to solve it please.

I have tried:

$month = 06;
$year = 2016;

$d = mktime(0, 0, 0, $month, 1, $year);
$td = date("Y-m-d", $d);
$oldDate = date('Y-m-d', strtotime("-3 Months"));

It gives me 3 months from current date. Any guesses how do I get the expected result ?

Upvotes: 1

Views: 67

Answers (4)

Bikash
Bikash

Reputation: 1938

Try this and you should get desired result.

$prev_month_ts = strtotime('2016-06 -3 month');

$prev_month = date('Y-m', $prev_month_ts);

echo $prev_month;

Upvotes: 0

RJParikh
RJParikh

Reputation: 4166

Use below. You need to use date("F Y", strtotime( INPUT_DATE ." -3 months"))

$month = 06;
$year = 2016;

$d = mktime(0, 0, 0, $month, 1, $year);
$td = date("Y-m-d", $d);
echo $olddate = date("Y-m-d", strtotime( $td ." -3 months"));
echo $months = date("F Y", strtotime( $td ." -3 months"));

Output:

2016-03-01
March 2016

Online Demo: Click Here

Upvotes: 1

J.K
J.K

Reputation: 1374

strtotime of (Input Date ."-3 Months")

$month = 06;
$year  = 2016;

$d       = mktime(0, 0, 0, $month, 1, $year);
$td      = date("Y-m-d", $d);
$oldDate = date('Y-m-d', strtotime($td."-3 Months"));

$oldDate_MonthYear = date('m-Y', strtotime($td."-3 Months"));

echo $oldDate;
echo '<br />';
echo $oldDate_MonthYear;

Upvotes: 1

balasubramani
balasubramani

Reputation: 19

Use Object Based.

$date1 = new DateTime("2016-06-01");
echo $startDate = $date1->modify("-3 month")->format('Y-m-d');

Upvotes: 0

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