CODEWITHSUNDEEP
php
user6239042
user6239042

Reputation:

Remove url from string but leave data in it by php

I have tried for it. But I could not do that, Here is my code

 $p = '|<a [^>]*href="http://<some url>[^"]*"[^>]*>.*</a>|iU';

 preg_replace($p, '$1', $a);

From above code I get all the link from that text, except the specific url. I want to get all the data in between link tag. Thats all.

Here is the link

<a href="http://<some url>"> <img src="Some url" alt="DZJarAP" width="213" height="300"></a>

I want it to be like

<img src="http://<some url>" alt="DZJarAP" width="213" height="300">

It may be any tag like img,p,div

Please help me out. Your answer are highly appreciable

Upvotes: 3

Views: 115

Answers (2)

Mohammad
Mohammad

Reputation: 21489

You can do this work using preg_match like this

preg_match("/^(<.*?>)(.*)(<.*?>)$/", $HTML, $matchs);
$imgsTag = $matchs[2];

It return every tag in <a>.

Upvotes: 1

Klaus F.
Klaus F.

Reputation: 145

This should help, if I got the correct question:

$p = '|<a href="(.*)">(.*").*(".*)</a>|iU';
preg_replace($p, '$2$1$3', $a);

It will result in:

 <img src="http://onlinegamesocean.com" alt="DZJarAP" width="213" height="300">

That only works if your tag in between has a link starting and ending with quotation marks. The link to replace must be the first quoted parameter. What a <p> and <div> tag have to do with a link is not clear from your question.

Upvotes: 0

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