CODEWITHSUNDEEP
iosregexswiftswift2nsregularexpression
Juanma M
Juanma M

Reputation: 11

NSRegularExpression error, I can't use Regular Expressions

I was creating a Regular expression but in can´t solve this problem 

class Regex {
    let internalExpression: NSRegularExpression
    let pattern: String

    init(_ pattern: String) {
        self.pattern = pattern
        var error: NSError?
        self.internalExpression = NSRegularExpression(pattern: pattern, options: .CaseInsensitive, error: &error)
    }

    func test(input: String) -> Bool {
        let matches = self.internalExpression.matchesInString(input, options: nil, range:NSMakeRange(0, countElements(input)))
        return matches.count > 0
    }
}

Here are the errors I got:

"Cannot invoke initializer for type 'NSRegularExpression' with an argument list of type '(pattern: String, options: _, error: inout NSError?)'"

and

"Use of unresolved identifier 'countElements'"

I only want to use this: 

if usuarioView.text! =~ "/^[a-zA-Z0-9_]{3,30}$/"

Upvotes: 1

Views: 1363

Answers (1)

JAL
JAL

Reputation: 42449

There are a few issues with your code. It looks like you are migrating from an earlier version of Swift to Swift 2.x.

The NSRegularExpression initializer has changed to throw its error instead of passing in an ErrorPointer:

do {
    self.internalExpression = try NSRegularExpression(pattern: pattern, options: .CaseInsensitive)
} catch {
    print(error)
}

To specific nil for an OptionType value, use []. To get the length of a string, use input.characters.count, since countElements has been removed from Swift:

let matches = self.internalExpression.matchesInString(input, options: [], range:NSMakeRange(0, input.characters.count))

Upvotes: 0

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