CODEWITHSUNDEEP
pythonrandom
Katz
Katz

Reputation: 866

How do I generate a ranndom number or letter with certain rules in python

I'm trying to generate a random number but with certain rules. The first 11 digits to be 00000001008 so I just made it a string and printed it to the screen then after the string, the next number is a random digit or a letter, so I'm using the random and string module to generate a random digit or letter. After the random generated number I want a set of three 1's so I just printed them as a string like I did with the first eleven values. But here's where I'm getting stuck, after the set of three 1's I want to generate another random number or letter and I can't figure it out, I tried the same line of code as the random variable, with a new variable name and then I tried to concatenate it with the new variable in the print statement and it gives me an error. How can I generate another random number after the three 1's?

import random 
import string

    random = ''.join([random.choice(string.ascii_letters + string.digits) for n in xrange(1)])

    print ("00000001008")+ random + ("111")

Output

00000001008U111

Desired Output

00000001008(random)111(random)1(random)

Error

import random 
import string

random = ''.join([random.choice(string.ascii_letters + string.digits) for n in xrange(1)])
random1 = ''.join([random.choice(string.ascii_letters + string.digits) for n in xrange(1)])
print ("00000001008")+ random + ("111") + random1

random1 = ''.join([random.choice(string.ascii_letters + string.digits) for n in xrange(1)]) AttributeError: 'str' object has no attribute 'choice'

Upvotes: 0

Views: 197

Answers (1)

lejlot
lejlot

Reputation: 66815

you can simply use string formatting and 3 random values

import random
import string

def gen():
  return random.choice(string.ascii_letters + string.digits)

print('00000001008%s111%s1%s' % (gen(), gen(), gen()))

and the only problem why your code is not working is that you named your variable random, which made module random impossible to access, thus error coming from your random.choice call which now refers to a string. Rename your variables to "random_string" and "random_string1" and everything will be just fine.

Upvotes: 4

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