CODEWITHSUNDEEP
ccolorshexrgb
Shavkat
Shavkat

Reputation: 139

Convert from HEX color to RGB struct in C

How do you convert from color HEX code to RGB in pure C using C library only (without C++ or templates)? The RGB struct may be like this: 

typedef struct RGB {
    double r;
    double g;
     double b;
} RGB1;

The function I'm looking for should return RGB1.

Upvotes: 13

Views: 59960

Answers (5)

therealcain
therealcain

Reputation: 353

I know this is quite old, but I wanted to give also a solution with unions and without any bitwise operations.

union Color
{
    unsigned int hex;
    struct { unsigned char b, g, r; };
};

This way you can convert from HEX to RGB and from RGB to HEX, easily.

union Color hex;
hex.hex = 0x07C73C;

union Color rgb;
rgb.r = 7;
rgb.g = 199;
rgb.b = 60;

printf("RGB(%d, %d, %d), HEX(%06x)", hex.r, hex.g, hex.b, rgb.hex);

Output:

RGB(7, 199, 60), HEX(07c73c)

and to map the values in the range of 0.0 to 1.0 you simply divide it by 255.0 :)

EDIT: The code above^^ is only supported under Little-Endian CPU's architecture, so a better way is to check what endianness does the system runs on.

Then you can check the endianness to define the order of the struct variables.

union Color
{
    unsigned int hex;

#if IS_BIG_ENDIAN
    struct { unsigned char a, r, g, b; };
#else
    struct { unsigned char b, g, r, a; };
#endif
};

This code also supports alpha ( transparency ) in RGBA.

Upvotes: 5

Tor Klingberg
Tor Klingberg

Reputation: 5098

If the hex code is a string, you can parse it like this

char *str = "0000FF";
int r, g, b;
sscanf(str, "%02x%02x%02x", &r, &g, &b);

That is to ints, not doubles. Also do check that sscanf returns 3, the number of items read.

Upvotes: 23

Andrey Pirozhenko
Andrey Pirozhenko

Reputation: 11

I guess RGB could be stored as 0xRRGGBB on some systems, but in Windows it is actually stored as 0xBBGGRR (see http://msdn.microsoft.com/en-us/library/windows/desktop/dd183449). As the article mentions, there are macros GetRValue, GetGValue, and GetBValue already available.

Upvotes: 1

cubic1271
cubic1271

Reputation: 1138

Assuming that your hex value is a 32-bit 'int' type, and that we use the RGB struct described above, then maybe do something like:

struct RGB colorConverter(int hexValue)
{
  struct RGB rgbColor;
  rgbColor.r = ((hexValue >> 16) & 0xFF) / 255.0;  // Extract the RR byte
  rgbColor.g = ((hexValue >> 8) & 0xFF) / 255.0;   // Extract the GG byte
  rgbColor.b = ((hexValue) & 0xFF) / 255.0;        // Extract the BB byte

  return rgbColor; 
}

Upvotes: 28

Matthew
Matthew

Reputation: 48304

An RGB value can be stored as in integer via 0xRRGGBB. Examples:

  • Red: 0xff0000
  • Green: 0x00ff00
  • Blue: 0x0000ff

00 is hex for decimal 0, while ff is 255. 0 corresponds to 0.0 and 255 to 1.0. (Actually you didn't specify what the range is. I'm assuming 0.0 to 1.0.)

So with the above assumptions, you need to extract each component and divide by 255. Since it sounds a lot like a homework question, I'll just show you how you can do the red component.

int hex = 0x123456;
c.r = ((hex >> 16) & 0xff) / 255.0;

Each hex digit takes up 4 bits. So shift to the right by 16 bits (to move everything 4 digits to the right) to make 0xRRGGBB become 0xRR. Now you have the red component. (Just in case there is some data higher up in the integer, you can get rid of it by masking the data via & 0xff.)

If you are dealing with a string "#FFFFFF", then you'd first have to convert it to an integer for the above to work.

Upvotes: 14

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