Reputation: 3060
From pd.date_range('2016-01', '2016-05', freq='M', ).strftime('%Y-%m')
, the last month is 2016-04
, but I was expecting it to be 2016-05
. It seems to me this function is behaving like the range
method, where the end parameter is not included in the returning array.
Is there a way to get the end month included in the returning array, without processing the string for the end month?
Upvotes: 24
Views: 27156
Reputation: 1
Use the explicit last dates pd.date_range(2016-01-31,2016-06-30, freq='M').
Upvotes: 0
Reputation: 21
start_date = '2021-09-10'
end_date = '2021-12-15'
value = pd.date_range(start=start_date, end=end_date, freq='M').union(pd.date_range(end=end_date, periods=1))
DatetimeIndex(['2021-09-30', '2021-10-31', '2021-11-30', '2021-12-15'], dtype='datetime64[ns]', freq=None)
Upvotes: 1
Reputation: 11
I had a similar problem when using datetime objects in dataframe. I would set the boundaries through .min() and .max() functions and then fill in missing dates using the pd.date_range function. Unfortunately the returned list/df was missing the maximum value.
I found two work arounds for this:
1) Add "closed = None" parameter in the pd.date_range function. This worked in the example below; however, it didn't work for me when working only with dataframes (no idea why).
2) If option #1 doesn't work then you can add one extra unit (in this case a day) using the datetime.timedelta() function. In the case below it over indexed by a day but it can work for you if the date_range function isn't giving you the full range.
import pandas as pd
import datetime as dt
#List of dates as strings
time_series = ['2020-01-01', '2020-01-03', '2020-01-5', '2020-01-6', '2020-01-7']
#Creates dataframe with time data that is converted to datetime object
raw_data_df = pd.DataFrame(pd.to_datetime(time_series), columns = ['Raw_Time_Series'])
#Creates an indexed_time list that includes missing dates and the full time range
#Option No. 1 is to use the closed = None parameter choice.
indexed_time = pd.date_range(start = raw_data_df.Raw_Time_Series.min(),end = raw_data_df.Raw_Time_Series.max(),freq='D',closed= None)
print('indexed_time option #! = ', indexed_time)
#Option No. 2 if the function allows you to extend the time by one unit (in this case day)
#by using the datetime.timedelta function to get what you need.
indexed_time = pd.date_range(start = raw_data_df.Raw_Time_Series.min(),end = raw_data_df.Raw_Time_Series.max()+dt.timedelta(days=1),freq='D')
print('indexed_time option #2 = ', indexed_time)
#In this case you over index by an extra day because the date_range function works properly
#However, if the "closed = none" parameters doesn't extend through the full range then this is a good work around
Upvotes: 1
Reputation: 747
The explanation for this issue is that the function pd.to_datetime()
converts a '%Y-%m'
date string by default to the first of the month datetime, or '%Y-%m-01'
:
>>> pd.to_datetime('2016-05')
Timestamp('2016-05-01 00:00:00')
>>> pd.date_range('2016-01', '2016-02')
DatetimeIndex(['2016-01-01', '2016-01-02', '2016-01-03', '2016-01-04',
'2016-01-05', '2016-01-06', '2016-01-07', '2016-01-08',
'2016-01-09', '2016-01-10', '2016-01-11', '2016-01-12',
'2016-01-13', '2016-01-14', '2016-01-15', '2016-01-16',
'2016-01-17', '2016-01-18', '2016-01-19', '2016-01-20',
'2016-01-21', '2016-01-22', '2016-01-23', '2016-01-24',
'2016-01-25', '2016-01-26', '2016-01-27', '2016-01-28',
'2016-01-29', '2016-01-30', '2016-01-31', '2016-02-01'],
dtype='datetime64[ns]', freq='D')
Then everything follows from that. Specifying freq='M'
includes month ends between 2016-01-01 and 2016-05-01, which is the list you receive and excludes 2016-05-31. But specifying month starts 'MS'
like the second answer provides, includes 2016-05-01 as it falls within the range. pd.date_range()
default behavior isn't like the range
method since ends are included. From the docs:
closed controls whether to include start and end that are on the boundary. The default includes boundary points on either end.
Upvotes: 0
Reputation: 1340
For the later crowd. You can also try to use the Month-Start frequency.
>>> pd.date_range('2016-01', '2016-05', freq='MS', format = "%Y-%m" )
DatetimeIndex(['2016-01-01', '2016-02-01', '2016-03-01', '2016-04-01',
'2016-05-01'],
dtype='datetime64[ns]', freq='MS')
Upvotes: 12
Reputation: 33783
You can use .union
to add the next logical value after initializing the date_range
. It should work as written for any frequency:
d = pd.date_range('2016-01', '2016-05', freq='M')
d = d.union([d[-1] + 1]).strftime('%Y-%m')
Alternatively, you can use period_range
instead of date_range
. Depending on what you intend to do, this might not be the right thing to use, but it satisfies your question:
pd.period_range('2016-01', '2016-05', freq='M').strftime('%Y-%m')
In either case, the resulting output is as expected:
['2016-01' '2016-02' '2016-03' '2016-04' '2016-05']
Upvotes: 14
Reputation: 19375
I dont think so. You need to add the (n+1) boundary
pd.date_range('2016-01', '2016-06', freq='M' ).strftime('%Y-%m')
The start and end dates are strictly inclusive. So it will not generate any dates outside of those dates if specified. http://pandas.pydata.org/pandas-docs/stable/timeseries.html
Either way, you have to manually add some information. I believe adding just one more month is not a lot of work.
Upvotes: 0
Reputation: 294218
A way to do it without messing with figuring out month ends yourself.
pd.date_range(*(pd.to_datetime(['2016-01', '2016-05']) + pd.offsets.MonthEnd()), freq='M')
DatetimeIndex(['2016-01-31', '2016-02-29', '2016-03-31', '2016-04-30',
'2016-05-31'],
dtype='datetime64[ns]', freq='M')
Upvotes: 16
Reputation: 294218
Include the day when specifying the dates in date_range
call
pd.date_range('2016-01-31', '2016-05-31', freq='M', ).strftime('%Y-%m')
array(['2016-01', '2016-02', '2016-03', '2016-04', '2016-05'],
dtype='|S7')
Upvotes: 1