CODEWITHSUNDEEP
javascriptregex
myhappycoding
myhappycoding

Reputation: 658

javascript regexp help selecting a word but no the first character

I am using javascript, and I am trying to work out how to select all characters of a word but no the first character.

For this, I am using regExpr. So the following expresion:

/\B[a-zA-Z'-]+/gi

should select all characters except the first one of each word, but it doesn't work for the text: "I'm a little tea pot" because of the apostrophe. I have tried everything, but dont know what else. I would apreciate any suggestion or support in this.

Thank you in advance!

Upvotes: 0

Views: 109

Answers (5)

guest271314
guest271314

Reputation: 1

Edit, Updated

You can use String.prototype.split() with RegExp /^.{1}|\s[a-z'-](?!=\s){1}|\s/ to exclude first character in word, match remainder of word; for loop, String.prototype.replace() to replace matched words returned by .split() following calling .toLowerCase() on matched word.

var str = "I'M a liTtLe tEa pOt";
console.log("original string:", str);
var res = str.split(/^.{1}|\s[a-z'-](?!\s)|\s/)
          .filter(Boolean); // `["'m", "ittle", "ea", "ot"]`
for (var i = 0; i < res.length; i++) {
  str = str.replace(res[i], res[i].toLowerCase())
};
console.log("res array:", res, "replaced string:", str);

You can use String.prototype.slice() with parameter 1 to return string excluding first character in str

console.log("I'm a little tea pot".slice(1))

or String.prototype.split() and Array.prototype.slice() to return array excluding first character in str

console.log("I'm a little tea pot".split("").slice(1))

Upvotes: 0

Resonance
Resonance

Reputation: 3786

enter image description here

s = "I'm a little tea pot, let's pour me out";
re = /(\B|')[a-z-']+/gi;
lastLettersArray = s.match(re);
console.log(lastLettersArray);

output

["'m", "ittle", "ea", "ot", "et's", "our", "e", "ut"]

Upvotes: 1

MrJomp
MrJomp

Reputation: 135

Try it here (Choose JS, PHP is default tab): http://regex.larsolavtorvik.com/

As simple as:

string.match(/\B\w+/gi);

Upvotes: 1

RomanPerekhrest
RomanPerekhrest

Reputation: 92854

Consider the following approach using String.split and Array.slice functions:

var str = "I'm a little tea pot", words = [];

str.split(" ").forEach((w) => w.length > 1 && words.push(w.slice(1)));

console.log(words);  // ["'m", "ittle", "ea", "ot"]

Or by using RegExp.exec function with regexp /\b\w([\w'-]+)\b/g:

var str = "I'm a little tea pot", words = "", res, re = /\b\w([\w'-]+)\b/g;

while ((res = re.exec(str)) != null){
    words += " " + res[1];
}

console.log(words);  // "'m ittle ea ot"

Upvotes: 1

Let Me Tink About It
Let Me Tink About It

Reputation: 16112

A matching regular expression pattern is as follows:

https://regex101.com/r/rW9sX5/2 
/\b\S(\S+)/gi

See the demo here.

Upvotes: 1

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