CODEWITHSUNDEEP
pythonvariablesfilesystemsoutputwatchdog
multipl3x_
multipl3x_

Reputation: 3

Getting the filename using python Watchdog

I am trying to get the name of a file that changes periodically. I am using watchdog to do this. 

import time
from watchdog.observers import Observer
from watchdog.events import FileSystemEventHandler

timestr = time.strftime("%Y.%m.%d-%H.%M.%S")

class MyHandler(FileSystemEventHandler):
    def on_modified(self, event):
        change_log = open('change_log_' + timestr + '.txt', 'aw')
        change_log.write('Time the file changed: ' + timestr + '\n')
        change_log.close()

if __name__ == "__main__":
    event_handler = MyHandler()
    observer = Observer()
    observer.schedule(event_handler, path='.', recursive=False)
    observer.start()

    try:
        while True:
            time.sleep(1)
    except KeyboardInterrupt:
        observer.stop()
    observer.join()

For some reason this prints out about 62 lines in the "change_log" file. This is not very useful. What I would like to do is to print the name of the file that changed, or store it in a variable to pass to my other module.

Upvotes: 0

Views: 6353

Answers (2)

Milovan Tomašević
Milovan Tomašević

Reputation: 8673

In your example, if you need a file name, it is necessary to replace 'change_log_' with event.src_path. See the official code for more details. You can also see the use of event.src_path in this answer as I used it in the printout.

Upvotes: 1

jerryabear
jerryabear

Reputation: 1

It looks like the event object that is sent to your handler includes the information that you seek: http://pythonhosted.org/watchdog/api.html#watchdog.events.FileSystemEvent

Use the src_path property of the event object that's passed into your FileSystemEvent subclass handler method to get the filename.

Upvotes: 0

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