CODEWITHSUNDEEP
arraysunderscore.jslodash
Dushyant Bangal
Dushyant Bangal

Reputation: 6403

lodash sort array of string arrays

I have the following data:

[["Balin Sankar","10","English","91.1408767700195"],
["Balin Sankar","10","Maths","88.1268997192383"],
["Balin Sankar","10","Science","90.3445739746094"],
["Balin Sankar","10","History","87.1235580444336"],
["Balin Sankar","10","Geography","88.2675628662109"],
["Balin Sankar","10","Civics","89.6238479614258"],
["Balin Sankar","10","Economics","86.5236434936523"]]

I need to sort these based on the 4th value

Upvotes: 0

Views: 2633

Answers (2)

Gruff Bunny
Gruff Bunny

Reputation: 27976

You could pass lodash's sortBy function a function that selects the fourth item in the list:

var result = _.sortBy(data, item => parseFloat(item[3]))


var data = [["Balin Sankar","10","English","91.1408767700195"],
["Balin Sankar","10","Maths","88.1268997192383"],
["Balin Sankar","10","Science","90.3445739746094"],
["Balin Sankar","10","History","87.1235580444336"],
["Balin Sankar","10","Geography","88.2675628662109"],
["Balin Sankar","10","Civics","89.6238479614258"],
["Balin Sankar","10","Economics","86.5236434936523"]]

var result = _.sortBy(data, item => parseFloat(item[3]))

var output = document.getElementById('result')

_.each(result, item => output.textContent += (item[2] + ' ' + item[3] + '\n'))
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.14.2/lodash.js"></script>

<p>
  <pre id="result"></pre>
</p>

Upvotes: 3

Tholle
Tholle

Reputation: 112857

You don't need lodash for that. It can be achieved with a regular sort:

var array = [["Balin Sankar","10","English","91.1408767700195"],
["Balin Sankar","10","Maths","88.1268997192383"],
["Balin Sankar","10","Science","90.3445739746094"],
["Balin Sankar","10","History","87.1235580444336"],
["Balin Sankar","10","Geography","88.2675628662109"],
["Balin Sankar","10","Civics","89.6238479614258"],
["Balin Sankar","10","Economics","86.5236434936523"]];

array.sort(function(a, b) {
  return a[3] - b[3];
});

console.log(array);

Upvotes: 1

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