CODEWITHSUNDEEP
bashshellsh
user3565529
user3565529

Reputation: 1367

Is there way to check if shell script is executed with -x flag

I am trying to check in the script, that if that script is executed with -x flag which is for the debugging for shell scripts. Is there any way to check that in script itself that -x is set. I want to conditionally check that and do something if that is set.

Upvotes: 5

Views: 1405

Answers (4)

Eric
Eric

Reputation: 1511

Look for xtrace in $SHELLOPTS.

For example:

if grep -q xtrace <<<"$SHELLOPTS"; then
    DO_SOMETHING;
fi

Upvotes: 0

creativeChips
creativeChips

Reputation: 1197

You can trap the DEBUG signal, like so:

trap "do_this_if_it_is_being_debugged" DEBUG

function do_this_if_it_is_being_debugged() {
...
}

Note this needs to be executed before the set -x is being executed

Upvotes: 2

dbosky
dbosky

Reputation: 1641

Use:

if [[ $- == *x* ]]; then
  echo "debug"
else
  echo "not debug"
fi

From Bash manual:

($-, a hyphen.) Expands to the current option flags as specified upon invocation, by the set builtin command, or those set by the shell itself (such as the -i option).

Upvotes: 10

Jens
Jens

Reputation: 72639

The portable way to do this (without bashisms like [[ ]]) would be

case $- in
(*x*) echo "under set -x"
esac

Upvotes: 2

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