Reputation: 161
I would like to display four images at the same time and upon form load the images switch places. Currently, images will appear in different numbers, for example: 1 image will appear or 2 images, etc up 4. I also want to ensure that no duplicates will appear.
Code from Form1_Load:
PictureBox[] boxes = new PictureBox[4];
boxes[0] = pictureBox0;
boxes[1] = pictureBox1;
boxes[2] = pictureBox2;
boxes[3] = pictureBox3;
for (int i = 0; i < boxes.Length; i++)
{
int switcher = r.Next(0, 5);
switch (switcher)
{
case 0:
{ boxes[i].Image = Properties.Resources.dog0; } break;
case 1:
{ boxes[i].Image = Properties.Resources.dog1; } break;
case 2:
{ boxes[i].Image = Properties.Resources.dog2; } break;
case 3:
{ boxes[i].Image = Properties.Resources.dog3; } break;
}
}
Two examples given above as to what currently happens.
Update - Working
The program now moves images around upon Load and there are no duplicates :)
List<Bitmap> resources = new List<Bitmap>();
resources.Add(Properties.Resources.dog0);
resources.Add(Properties.Resources.dog1);
resources.Add(Properties.Resources.dog2);
resources.Add(Properties.Resources.dog3);
resources = resources.OrderBy(a => Guid.NewGuid()).ToList();
for (int i = 0; i < resources.Count; i++)
{
pictureBox0.Image = resources[0];
pictureBox1.Image = resources[1];
pictureBox2.Image = resources[2];
pictureBox3.Image = resources[3];
}
Two example given above showing what happens now that it works.
Upvotes: 2
Views: 1556
Reputation: 4077
The implementation is quite simple. Firstly, you need to shuffle the array and then iterate through it. Fisher–Yates shuffle.
Create a method ShuffleImages
as below:
public void ShuffleImages(PictureBox[] img)
{
Random r = new Random();
for (int i = 0; i < img.Length - 1; i++)
{
int j = r.Next(i, img.Length);
PictureBox temp = img[j];
img[j] = img[i];
img[i] = temp;
}
}
and call the method in your Form1_Load
event:
private void Form1_Load(object sender, EventArgs e)
{
PictureBox[] boxes = new PictureBox[4];
boxes[0] = pictureBox0;
boxes[1] = pictureBox1;
boxes[2] = pictureBox2;
boxes[3] = pictureBox3;
ShuffleImages(boxes); //call the method
for (int i = 0; i <= 3; i++)
{
switch (i)
{
case 0:
{ boxes[i].Image = Properties.Resources.dog0; }
break;
case 1:
{ boxes[i].Image = Properties.Resources.dog1; }
break;
case 2:
{ boxes[i].Image = Properties.Resources.dog2; }
break;
case 3:
{ boxes[i].Image = Properties.Resources.dog3; }
break;
}
}
}
Upvotes: 1
Reputation: 1344
As M.kazem Ahkhary points out you need to shuffle the images:
List<Bitmap> resources = new List<Bitmap>();
resources.Add(Properties.Resources.dog0);
resources.Add(Properties.Resources.dog1);
resources.Add(Properties.Resources.dog2);
resources.Add(Properties.Resources.dog3);
resources = resources.OrderBy(a => Guid.NewGuid()).ToList(); // Dirty but effective shuffle method
pictureBox0.Image = resources[0];
pictureBox1.Image = resources[1];
pictureBox2.Image = resources[2];
pictureBox3.Image = resources[3];
Upvotes: 1