CODEWITHSUNDEEP
javatomcatservlets
CrazySynthax
CrazySynthax

Reputation: 15058

What is the URL for a Java Servlet

I opened a Maven project in IntelliJ trying to deploy a Java servlet. This is the class I wrote: 

import java.io.*;
import javax.servlet.*;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.*;

@WebServlet("/home")
public class SimpleServlet extends HttpServlet {

    @Override
    protected void doGet(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {
        resp.getWriter().write("Hello World");
    }
}

and when I do "tomcat7:redeploy", I get a message that build is successful: 

[INFO] tomcatManager status code:200, ReasonPhrase:OK [INFO] OK -
Deployed application at context path /JavaCourse [INFO]
------------------------------------------------------------------------ 
[INFO] BUILD SUCCESS

Now, I want to know what should be the URL address that I have to type in the browser to get the servlet.

I tried localhost:8080/home and I got an error. Can you please help me?

Upvotes: 0

Views: 795

Answers (3)

Chris Wilson
Chris Wilson

Reputation: 46

Tomcat deployed your application to 'localhost:8080/JavaCourse/', not just 'localhost:8080/'

You should be able to access this particular servlet at localhost:8080/JavaCourse/home

Upvotes: 1

user330315
user330315

Reputation:

The full URL of a servlet includes the context into which the web application was deployed.

As you deployed it to /JavaCourse the URL of the servlet is:

http://localhost:8080/JavaCourse/home

Upvotes: 1

Paul
Paul

Reputation: 1071

It should be localhost:8080/%your_project_name%/home. Not straightly localhost:8080/home.

Upvotes: 1

Related Questions