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Ben
Ben

Reputation: 3804

Remove Last Two Characters in a String

Is there a quick way to remove the last two characters in a String in Swift? I see there is a simple way to remove the last character as clearly noted here. Do you know how to remove the last two characters? Thanks!

Upvotes: 80

Views: 63447

Answers (5)

Leo Dabus
Leo Dabus

Reputation: 236340

update: Xcode 9 • Swift 4 or later

String now conforms to RangeReplaceableCollection so you can use collection method dropLast straight in the String and therefore an extension it is not necessary anymore. The only difference is that it returns a Substring. If you need a String you need to initialize a new one from it:

let string = "0123456789"
let substring1 = string.dropLast(2)         // "01234567"
let substring2 = substring1.dropLast()      // "0123456"
let result = String(substring2.dropLast())  // "012345"

We can also extend LosslessStringConvertible to add trailing syntax which I think improves readability:

extension LosslessStringConvertible {
    var string: String { .init(self) }
}

Usage:

let result = substring.dropLast().string

Upvotes: 169

Guillaume Ramey
Guillaume Ramey

Reputation: 263

Better to use removeLast()

var myString = "Hello world"
myString.removeLast(2)

output : "Hello wor"

Upvotes: 2

Deepak Tagadiya
Deepak Tagadiya

Reputation: 2237

swift 4:

let str = "Hello, playground"
let newSTR1 = str.dropLast(3)
print(newSTR1) 

output: "Hello, playgro"

//---------------//

let str = "Hello, playground"
let newSTR2 = str.dropFirst(2)
print(newSTR2)

output: "llo, playground"

Upvotes: 27

Naveen Ramanathan
Naveen Ramanathan

Reputation: 2206

var name: String = "Dolphin"
let endIndex = name.index(name.endIndex, offsetBy: -2)
let truncated = name.substring(to: endIndex)
print(name)      // "Dolphin"
print(truncated) // "Dolph"

Upvotes: 61

Andy Obusek
Andy Obusek

Reputation: 12832

Use removeSubrange(Range<String.Index>) just like:

var str = "Hello, playground"
str.removeSubrange(Range(uncheckedBounds: (lower: str.index(str.endIndex, offsetBy: -2), upper: str.endIndex)))

This will crash if the string is less than 2 characters long. Is that a requirement for you?

Upvotes: 1

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