CODEWITHSUNDEEP
c++classnumbers
Shifter
Shifter

Reputation: 11

Overloading *= for complex numbers

Im having trouble getting down the arithmetic for the a function (a+bi)*(c+di) which is the same as (ac-bd) + (ad+bc) with the overloaded operator ( *= ) so far i have this for my overloaded function. For my definition to the overloaded *= i dont know what to write to include the -bd part of (ac-bd). 

#include <iostream>

using std::cout;
using std::cin;
using std::endl;

class Complex {
public:
    Complex(double = 0, double = 0);
    void print() const { cout << real << '\t' << imag << '\n'; }
    // Overloaded +=
    Complex& operator +=(const Complex&);
    // Overloaded -=
    Complex& operator -=(const Complex&);
    // Overloaded *=
    Complex& operator *=(const Complex&);
    // Overloaded /=
    Complex& operator /=(const Complex&);
    double Re() const { return real; }
    double Im() const { return imag; }
private:
    double real, imag;
};

int main()
{
    Complex x, y(2), z(3, 4.5), a(1, 2), b(3, 4);
    x.print();
    y.print();
    z.print();
    y += z;
    y.print();
    a *= b;
    a.print();
    return 0;
}

Complex::Complex(double reel, double imaginary)
{
    real = reel;
    imag = imaginary;
}

// Return types that matches the one in the prototype = &Complex
Complex& Complex::operator+=(const Complex& z)
{
    real += z.Re();
    imag += z.Im();
    //How to get an object to refer to itself
    return *this;
}
Complex& Complex::operator *= (const Complex& z)
{
    real *= (z.Re());
    imag *= z.Re();
    return *this;
}

Upvotes: 0

Views: 718

Answers (1)

Brian Bi
Brian Bi

Reputation: 119144

You can perform multiple assignment using std::tie and std::make_tuple:

std::tie(real, imag) = std::make_tuple(real*z.real - imag*z.imag,
                                       real*z.imag + imag*z.real);
return *this;

Upvotes: 3

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