CODEWITHSUNDEEP
pythondictionary
Rookie
Rookie

Reputation: 429

Convert nested dictionary values to single string

How can I convert the below nested dictionary values to a single string ?

data = {'people': {'first': {'fname': 'P1', 'lname': 'L1'}, 'second': { 'fname': 'P2', 'lname': 'L2'}}}

Output should be P1 L1, P2 L2

Here is my current code: 

print ', '.join("%s %s" % (data['people'][person].get('fname'), data['people'][person].get('lname')) for person in data['people'])

Is this a efficient way for a larger set to items in people dict ? If not how to improve this ?

Upvotes: 2

Views: 5318

Answers (5)

Ashwini Chaudhary
Ashwini Chaudhary

Reputation: 251156

You can make your expression a bit short by only looping over just values and using named field in format string(Emphasis is to keep it more readable):

>>> print ', '.join("{fname} {lname}".format(**p) for p in data['people'].values())
P2 L2, P1 L1

In Python 3.2+ this can also be done using str.format_map:

>>> print (', '.join("{fname} {lname}".format_map(p) for p in data['people'].values()))
P1 L1, P2 L2

If the keys fname or lname might be missing from the dicts then you could do something like this:

def get_values(dct, keys):
    return (dct.get(k) for k in keys)
...
>>> keys = ('fname', 'lname')
>>> print ', '.join("{} {}".format(*get_values(p, keys)) for p in data['people'].values())
P2 L2, P1 L1
  • If number of values are huge then replace values() with itervalues(). In Python 3 use values() only.
  • Dicts don't have any specified order, so you cannot expect the output to be P1 L1, P2 L2 here.

Upvotes: 2

chanchal pardeshi
chanchal pardeshi

Reputation: 167

one = data['people']['second'].values()
two = data['people']['first'].values()

three = one + two
three.reverse()


for each in three:
  print each,

I hope this what you are looking for.

Upvotes: 0

minji
minji

Reputation: 512

result = list()
for person in data["people"]:
    for val in data["people"][person].values():
        result.append(val)
    result.append(", ")
result.pop()
print(' '.join(result))

or

result = list()
for person in data["people"]:
    result.append(data["people"][person]["fname"])
    result.append(data["people"][person]["lname"])
    result.append(", ")
result.pop()
print(' '.join(result))

Upvotes: 0

jonatan
jonatan

Reputation: 135

Your data structure is recursive so you'll need a recursive function to obtain them

def get_values(data):
    values = []
    for k, v in data.items():
        if isinstance(v, dict):
            values.extend(get_values(v))
        else:
            values.append(v)
    return values

Upvotes: 1

harshil9968
harshil9968

Reputation: 3244

data = {'people': {'first': {'fname': 'P1', 'lname': 'L1'}, 'second': { 'fname': 'P2', 'lname': 'L2'}}}


def myprint(d):
  for k, v in d.iteritems():
    if isinstance(v, dict):
      myprint(v)
    else:
      print "{0} : {1}".format(k, v)

myprint(data)

Upvotes: -1

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